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o-na [289]
3 years ago
9

A block of mass m is pushed up against a spring with spring constant k until the spring has been compressed a distance x from eq

uilibrium. what is the work done on the block by the spring.
A. W=kx^2
B.W=-kx^2
C.W=0
D. None of these
Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:d

Explanation:

Spring is compressed to a distance of x from its equilibrium position

Work done by block on the spring is equal to change in elastic potential energy

i.e. Work done by block W=\frac{1}{2}kx^2

therefore spring will also done an equal opposite amount of work on the block in the absence of external force

Thus work done by spring on the block W=-\frac{1}{2}kx^2

Thus option d is correct

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2,3,4

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How much force is needed to stop a 50 kg gymnast if he decelerates at 25 m/s^2
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The force can be calculated by multiplying the mass of the gymnast with her acceleration.

Force = 50 kg × 25 m/s2
Force = 1250 N

A force of at least 1250 N can stop the 50-kg gymnast.

I hope I was able to answer your question. Have a good day.
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The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?
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Answer:

Option B. N2(g) + 3H2(g) → 2NH3(g)

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N2+ 3H2 → 2NH3

Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation

4 0
3 years ago
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A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal
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Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is
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Answer: 78 N-s
3 0
3 years ago
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1. Calculate the power it takes for a 583 N student to climb up1.5 m stairs in 2.1 seconds. (find work first!)GivenFormulaSubsti
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Given data

*The given force is F = 583 N

*The given distance is s = 1.5 m

*The given time is t = 2.1 s

The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

P=\frac{F\mathrm{}s}{t}

Substitute the known values in the above expression as

\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W

3 0
1 year ago
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