Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
Answer:

Explanation:
As we know that when astronaut is revolving in circular path then the acceleration of the astronaut is due to centripetal acceleration
so it is given as

here we know that

also we know that

now we have


B
Weight is caused by the influence of gravity on matter/mass. Weight is given by the formulae;
Weight = Mass * Gravitational acceleration
On earth, the gravitation acceleration is a constant 10m/s2
Therefore the weight will be influenced by mass of the object in a direct relationship.
An increase in mass will cause a proportionate increase in weight.
Explanation:
Gravity is not constant across the universe with larger celestial bodies have a greater gravitational pull. Therefore an object with the same mass on earth may weigh differently on another celestial body with different gravitational acceleration. An example is the Moon. Due to the fact that the Moon has approximately ¹/3 of earth’s gravitational force, astronauts weight ¹/3 times less on the moon than on earth.
Learn More:
For more on weight and mass check out;
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Power<span> is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. We express it as follows:
P = W / t
where W = Fd
F = mg
Therefore,
P = mgd / t
P = (30)(9.81)(20) / 1 = 5886 W</span>
Technically it is referred to as <em>star brightness</em> but yes you have the general idea.