first is gamma Ray's, last is d
Answer:
solution
we know that .
s=ut+½at²
now, putting the values in the second equation of motion ,
we get,
S=20×10+1/2×(10)²
S=200+1×100
S=200+100
S=300m
the distance covered by given body or object in 10 seconds is 300 m.
Answer:
7.0s
Explanation:
Mass = 0.41kg
F= 81N
t = 0.22s
¤ = 29°
Lo = 86m
From impulse equation,
F*t = m* v
81 * 0.22 = 0.41 * v
Vo = 17.82 / 0.41
Vo = 43.46m/s
Vx= velocity across horizontal plane
Vy = velocity across vertical plane
Vx = Vo * cos ¤
Vy = Vo * sin ¤
Vx = 43.46 * cos 30° = 37.64 m/s
Vy = 43.46 sin 30° = 21.73 m/s
Distance travelled across the vertical plane,
L = Lo + Vy *t + ½gt²
0 = 86 + 21.73t - 4.9t²
4.9t² - 21.73t - 86 = 0
Solving for t in the quadratic equation,
t = 6.96 or -10.04
Using the positive root since time can't be negative, t = 6.96 approximately 7.0s
Answer:
The speed of the bus is 40 km/hr so this means the bus is travelling at a speed of 40 km per hour.
