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3 years ago

13

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pre

ssure?

1 answer:

Fed [463]3 years ago

7 0

Answer:

893K=620 °C

Explanation:

PV=nRT

P=nRT/V

P= (1 mol* 0.0821* 298K)/15L P=1.63 atm

T=PV/nR

T=(1.63 atm*45 L)/(1 mol*0.0821)

T= 893K=620 °C

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