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klio [65]
3 years ago
10

How many moles of Iron Fe, are in 0.054g of iron?​

Chemistry
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

9.643×10^-4 mole is your answer

Explanation:

56 g of iron =1 mole

0.054 g of iron =1×0.054/56=9.643×10^-4 mole

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A nucleotide is composed of a(n) _____.
Gnom [1K]

Answer : A nucleotide is composed of a phosphate group and a nitrogen-containing base.

Explanation :

Nucleotide : It is a building block of nucleic acids or we can say that it is building block of DNA and RNA.

It is composed of three sub-unit molecules which are a nitrogenous base, a five-carbon sugar and one phosphate group.

Nucleotide forms covalent bonds with other nucleotide for the formation of the nucleic acid strand.

Hence, a nucleotide is composed of a phosphate group and a nitrogen-containing base.

5 0
3 years ago
A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to
Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure P_{1} = 1.03 atm = 104.325 K pa

Initial temperature T_{1} = 26 °c = 299 K

Initial volume V_{1} = 22.4 L

Final temperature T_{2} = 22 °c = 295 K  

Final pressure P_{2} = 0.81 atm = 82 K pa

We know that

\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }

Put all the values in above formula we get

\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}

V_{2} = 28.11 L

This is the final volume of the balloon.

8 0
3 years ago
Perform an on-line search to discover what conditions are favourable to the growth of moss. be sure to include a comment on ph c
Genrish500 [490]
Moss can grow abundantly in an environment with favorable conditions. They usually grow abundantly in cool, moist and dark places. If not dark, they prefer shady areas. Also, they tend to grow in acidic soil with pH range between 5.0-5.5. 
4 0
4 years ago
the elements carbon hydrogen and oxygen are all part of the same blank on the periodic table........ i i think GROUP diangol row
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6 0
3 years ago
20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc
bezimeni [28]

Answer:

Concentration of the barium ions  = [Ba^{2+}] = 0.4654 M

Concentration of the chloride ions  = [Cl^{-}]=0.9308 M

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride  = 0.1355 M

n=0.1355 M\times  0.04389 L=0.005947 mol

Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

\frac{1}{2}\times 0.05947 mol=0.029735 mol barium hydroxide

Moles of barium hydroxide = 0.029735 mol

Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

=1\times 0.029735 mol= 0.029735 mol

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL  = 63.89 mL = 0.06389 L

Concentration of the barium ions =[Ba^{2+}]

[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M

Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M

8 0
3 years ago
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