Answer:
hot components or sharp edges of computer is an example of a mechanical hazard
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n;
double average,sum=0,x;
cout<<"enter the Value of N:";
// read the value of N
cin>>n;
cout<<"enter "<<n<<" Numbers:";
// read n Numbers
for(int a=0;a<n;a++)
{
cin>>x;
// calculate total sum of all numbers
sum=sum+x;
}
// calculate average
average=sum/n;
// print average
cout<<"average of "<<n<<" Numbers is: "<<average<<endl;
return 0;
}
Explanation:
Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.
Output:
enter the Value of N:5
enter 5 Numbers:20.5 19.7 21.3 18.6 22.1
average of 5 Numbers is: 20.44
Answer:
The definition including its given problem is outlined in the following segment on the clarification.
Explanation:
- Entity-relationship (ER) diagram describes how mechanical stored procedures are constructed and demonstrate the overarching representation of the situation. It also describes the connections between some of the entities of the framework and even the comparison with standard measurements.
- For something like an individual relationship structure, the normal representation of connections seems to be a diamond. Associative institutions have several to many partnerships to communicate with. It's indeed the verb throughout a diamond-shaped form that holds two organizations around each other. This verb is in fact an entity on its own, therefore it must be termed an associative entity.
- An illustration of such might be if a participant were to register for a class. Multiple individuals will be registered for several courses, and there have been many to several relationships; thus, the associative object will indeed register.
Answer:
Check the explanation
Explanation:
# Step 1
the first thing to execute will be......
f = open("states.txt")
# Step 2
the second step is......
states = []
for line in f:
states.append(line.strip())
# Step 3:
the third step is to......
for state in sorted(states):
print(state)
f.close()
Answer:
nrToCheck = int(input("How many numbers do you need to check? "))
nrEven = 0
nrOdd = 0
for i in range(nrToCheck):
number = int(input("Enter number: "))
if (number % 2):
nrOdd = nrOdd + 1
print("{} is an odd number".format(number))
else:
nrEven = nrEven + 1
print("{} is an even number".format(number))
print("You entered {} even number(s).".format(nrEven));
print("You entered {} odd number(s).".format(nrOdd));
