Answer:
403.2 L of O2
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO3 —> 2KCI + 3O2
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Next, we shall determine the number of mole of O2 produced by the decomposition of 12 moles of KClO3. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Therefore, 12 moles of KClO3 will decompose to produce = (12 × 3)/2 = 18 moles of O2.
Thus, 18 moles of O2 is produced.
Finally, we shall determine the volume of O2 produced from the reaction. This can be obtained as illustrated below:
Recall: 1 mole of any gas occupy 22.4 L at STP.
1 mole of O2 occupies 22.4 L at STP.
Therefore, 18 moles of O2 will occupy = 18 × 22.4 = 403.2 L at STP.
Thus, 403.2 L of O2 is produced from the reaction.
