Ask question

Ask question

All categories

3 years ago

12

According to the primordial soup model, which statement tells how the chemicals in Earth’s prehistoric surface came alive? A. Vo

lcanic eruptions caused change in the chemicals. B. A huge meteor struck the earth and caused the chemicals to change. C. Cooler temperatures caused the chemicals to split apart. D. Storms and lightning caused some chemicals to be combined.

2 answers:

Nikolay [14]3 years ago

3 0

<span> A huge meteor struck the earth and caused the chemicals to change.</span>

bija089 [108]3 years ago

3 0

Answer:

It is D!!!

Explanation:

I took this test got it right :)

You might be interested in

H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).

timofeeve [1]

Answer:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

an equilibrium constant is, first of all, a fraction;
in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
each concentration should be raised to the power of the coefficient in the balanced chemical equation;
only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

$K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}$

4 0

4 years ago

What is kept the same in a controlled experiment

Serhud [2]

Answer:

Variables and independent variables

4 0

2 years ago

a 40-lb container of peat moss measure 14x20x30 inches and has an average density of 0.13 g/cm^3. how many bags of peat moss are

telo118 [61]

Volume of the peat moss = $14\times 20\times 30 inches$

= $8400 in^{3}$

Convert the above volume into $cm^{3}$

$1 in^{3}= 16.4 cm^{3}$

Thus, volume in $cm^{3}$ is:

Volume of peat moss = $8400 in^{3}\times \frac{16.4 cm^{3}}{1 in^{3}}$

= $137760 cm^{3}$

Now,

Total volume by using area and depth of the peat moss = $area of peat moss \times depth of peat moss$

= $(13 ft \times 25 ft)\times 1.9 inches$

= $(325 ft^{2})\times 1.9 inches$

Convert above values in $cm$ to get the value of volume in $cm^{3}$ :

$1 ft= 30.48 cm$

$1 in= 2.54 cm$

Thus, volume in $cm^{3}$ is:

Total volume = $(325 ft^{2}\times\frac{(30.48 cm)^{2}}{(1 ft)^{2}})\times (1.9 in\times \frac{2.54 cm}{1 in})$

= $301934.88 cm^{2}\times 4.826 cm$

= $1457137.73088 cm^{3}$

Now, number of bags is calculated by the ratio of total volume of the peat moss to the volume of the peat moss.

$Number of bags =\frac{total volume of peat moss}{volume of peat moss}$

Substitute the values of volume in above formula:

$Number of bags = \frac{1457137.73088 cm^{3}}{137760 cm^{3}}$

= $10.57$

≅ $11$ bags

Thus, number of bags of peat moss are needed to cover an area measure $13 ft$ by $25 ft$ to a depth of $1.9 inches$ are $11$ bags.

4 0

3 years ago

What five things is the element carbon part of??

fgiga [73]

It is part of oceans, air, rocks, soil and all living things. Carbon doesn't stay in one place. It is always on the move! In the atmosphere, carbon is attached to oxygen in a gas called carbon dioxide.

Hope this helps.

7 0

3 years ago

Which BEST describes how an experiment should be designed?

vova2212 [387]

Answer:

form a hypothesis.

5 0

3 years ago