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Rama09 [41]
3 years ago
7

An engineer is trying to create a fast reaction in a fuel mixture. Which should she do? A. Decrease the amount of fuel B. Lower

the temperature of the engine C. Add a catalyst to the fuel mixture D. Lower k for the fuel reaction
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
3 0
To increase the rate of a reaction, you can either do any of the following:
-increase the temperature
-increase concentration of the aqueous reactant
-increase pressure of the gas
-use a catalyst
-increase surface area of the solid reactant

From these, the engineer should therefore do C. Adding a catalyst speeds up the reaction without really joining the reaction.
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A certain mass of carbon reacts with 9.53 g of oxygen to form carbon monoxide. ________ grams of oxygen would react with that sa
yawa3891 [41]

Answer: 9.53 *2= 19.06

Explanation:

The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.

in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.

But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.

CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.

3 0
2 years ago
What happens to the rate of dissolution as the temperature is increased in a gas solution?
Nina [5.8K]

Answer:

The rate decreases

Explanation:

When we dissolve a gas in a water, the process is exothermic. This implies that heat is evolved upon dissolution of a gas in water.

Recall from Le Chateliers principle that for exothermic reactions, an increase in temperature favours the reverse reaction. The implication of these is that when the temperature of the gas is increased, less gas will dissolve in water.

Hence increase in temperature decreases the rate of solubility of a gas in water.

8 0
2 years ago
Two major discoveries of the gold foil experiment
tiny-mole [99]
Rutherford's gold foil experiment proved that there was a small, dense, positively charged nucleus at the center, which contained most of the mass of the atom. Which contained electrons orbiting the nucleus.
5 0
3 years ago
When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo
Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

b)

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

3 0
3 years ago
A 0.0100 M solution of AgNO3 has a concentration of Ag ion equivalent to
qaws [65]

Answer:

0.0100M of AgNO3 contains 0.0100M of Ag+

Explanation:

AgNO3 when ionized yields Ag+ and NO3-. This means that the amount of AgNO3 in solution is equivalent to the amount of Ag+ and NO3- in that same solution.

1M of AgNO3 solution produces 1M of Ag+  

1M of AgNO3 solution produces 1M of NO3-

This occurs because of the complete ionization of AgNO3 in solution, allowing complete dissolution of the compound.

6 0
2 years ago
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