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Rama09 [41]
3 years ago
7

An engineer is trying to create a fast reaction in a fuel mixture. Which should she do? A. Decrease the amount of fuel B. Lower

the temperature of the engine C. Add a catalyst to the fuel mixture D. Lower k for the fuel reaction
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
3 0
To increase the rate of a reaction, you can either do any of the following:
-increase the temperature
-increase concentration of the aqueous reactant
-increase pressure of the gas
-use a catalyst
-increase surface area of the solid reactant

From these, the engineer should therefore do C. Adding a catalyst speeds up the reaction without really joining the reaction.
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Two atoms that are isotopes of one another must have the same number of what? Electrons, All Particles, Protons, or Neutrons
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atoms are made of 3 types of sub atomic particles; neutrons, protons and electrons

atomic number is the number of protons which is characteristic for the element. Atoms of the same element have the same number of protons.

mass number is the sum of the neutrons and protons.

Isotopes are atoms of the same element with different mass numbers. since they are the same element number of protons are the same but number of neutrons vary.

therefore 2 isotopes are of the same element so they have the same number of protons.

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A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
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1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

6) mass of the empirical formula

14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
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