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Rama09 [41]
4 years ago
7

An engineer is trying to create a fast reaction in a fuel mixture. Which should she do? A. Decrease the amount of fuel B. Lower

the temperature of the engine C. Add a catalyst to the fuel mixture D. Lower k for the fuel reaction
Chemistry
1 answer:
oksano4ka [1.4K]4 years ago
3 0
To increase the rate of a reaction, you can either do any of the following:
-increase the temperature
-increase concentration of the aqueous reactant
-increase pressure of the gas
-use a catalyst
-increase surface area of the solid reactant

From these, the engineer should therefore do C. Adding a catalyst speeds up the reaction without really joining the reaction.
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3. Which is not a disturbance of an ecosystem?
Lyrx [107]
A decomposer is not a disturbance of the ecosystem because it decomposes dead animal bodies and recycles it into the soil which helps the food chain work
3 0
3 years ago
The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor
vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

3 0
4 years ago
Which statements are true concerning our interpretation of the results of an experiment?
miskamm [114]

Answer:

3. Judgement may be affected by what we already think is true (prior knowledge).

Explanation:

This statement is the correct answer because someone could be bias. Due to biases, prior knowledge may be incorrect and our conclusion may be wrong if you don't focus on the data given.

7 0
3 years ago
When a metal was exposed to light at a frequency of 4.07× 1015 s–1, electrons were emitted with a kinetic energy of 3.30× 10–19
Licemer1 [7]

Answer :  The maximum number of electrons released = 1.432\times 10^{12}electrons

Explanation : Given,

Frequency = 4.07\times 10^{15}s^{-1}

Kinetic energy = 3.30\times 10^{-19}J

Total energy = 3.39\times 10^{-7}J

First we have to calculate the work function of the metal.

Formula used :

K.E=h\nu -w

where,

K.E = kinetic energy

h = Planck's constant = 6.626\times 10^{-34}J/s

\nu = frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

3.30\times 10^{-19}J=(6.626\times 10^{-34}J/s\times 4.07\times 10^{15}s^{-1})-w

By rearranging the terms, we get

w=2.367\times 10^{-18}J

Therefore, the works function of the metal is, 2.367\times 10^{-18}J

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released = \frac{\text{ Total energy}}{\text{ work function}}

The maximum number of electrons released = \frac{3.39\times 10^{-7}J}{2.367\times 10^{-19}J}=1.432\times 10^{12}electrons

Therefore, the maximum number of electrons released is 1.432\times 10^{12}electrons

8 0
3 years ago
There are two different isotopes of bromine atoms. Under normal conditions, elemental bromine consists of Br2 molecules, and the
Anon25 [30]
Your answer would be A and D love!
3 0
3 years ago
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