Answer:
1. 5.12068 × 1011 N/C away from the proton
Explanation:
The electric field produced by a single point charge is given by:
![E=k\frac{q}{r^2}](https://tex.z-dn.net/?f=E%3Dk%5Cfrac%7Bq%7D%7Br%5E2%7D)
where
k is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the charge of the proton
is the distance at which we want to calculate the field
is the Coulomb's constant
Substituting into the formula,
![E=(8.99\cdot 10^9 Nm^2C^{-2})\frac{1.6\cdot 10^{-19}C}{(5.3\cdot 10^{-11}m)^2}=5.12068\cdot 10^{11} N/C](https://tex.z-dn.net/?f=E%3D%288.99%5Ccdot%2010%5E9%20Nm%5E2C%5E%7B-2%7D%29%5Cfrac%7B1.6%5Ccdot%2010%5E%7B-19%7DC%7D%7B%285.3%5Ccdot%2010%5E%7B-11%7Dm%29%5E2%7D%3D5.12068%5Ccdot%2010%5E%7B11%7D%20N%2FC)
And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is
1. 5.12068 × 1011 N/C away from the proton