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GenaCL600 [577]
2 years ago
5

Which of Newton's laws of motion describes the motion of an object that has a net force of ON?

Physics
1 answer:
algol [13]2 years ago
3 0

Newton's first and second laws of motion both do, but I think the one you're looking for is: <em>The First Law of Motion</em>.  That description is a little more direct.

It says that if an object is not acted on by a net external force, then it continues in "constant, uniform motion".

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What is the correct order of the layers' density from lowest density to highest?
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Answer:

C. crust, mantle, core

Explanation:

density increases as you travel from the crust to the inner core

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6 0
3 years ago
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Which of Newton’s laws of accounts for the following statement?
Neko [114]
The answer is B


second law
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Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo
olya-2409 [2.1K]

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

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7 0
3 years ago
A car jack with a mechanical advantage of 6 needs to produce an output force of 600 N to raise a car. What input force is requir
Mkey [24]

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6 0
3 years ago
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6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hour
Kisachek [45]

Answer:

Total distance, d=\dfrac{xyt}{(x+y)}

Explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to, \dfrac{d}{x}

Similarly, when he move back to home, time taken is equal to \dfrac{d}{y}

Total time taken is equal to :

\dfrac{d}{x}+\dfrac{d}{y}=t

d(\dfrac{1}{x}+\dfrac{1}{y})=t

d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}

d=\dfrac{xyt}{(x+y)}

So, the distance he speed in walking and jogging is \dfrac{xyt}{(x+y)}. Hence, this is the required solution.

8 0
2 years ago
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