Answer:
The average speed of the blood in the capillaries is 0.047 cm/s.
Explanation:
Given;
radius of the aorta, r₁ = 1 cm
speed of blood, v₁ = 30 cm/s
Area of the aorta, A₁ = πr₁² = π(1)² = 3.142 cm²
Area of the capillaries, A₂ = 2000 cm²
let the average speed of the blood in the capillaries = v₂
Apply continuity equation to determine the average speed of the blood in the capillaries.
A₁v₁ = A₂v₂
v₂ = (A₁v₁) / (A₂)
v₂ = (3.142 x 30) / (2000)
v₂ = 0.047 cm/s
Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.
As the ball is moving in air as well as we have to neglect the friction force on it
So we can say that ball is having only one force on it that is gravitational force
So the force on the ball must have to be represented by gravitational force and that must be vertically downwards
So the correct FBD will contain only one force and that force must be vertically downwards
So here correct answer must be
<em>Diagram A shows a box with a downward arrow. </em>
1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>
Answer:
may be upside down alphabet :"T"
Explanation:
Answer:
Answer:
the amount of energy flowing is 1.008x10⁹J
Explanation:
To calculate how much heat flows, the expression is the following:
Where
K=thermal conductivity=0.81W/m°C
A=area=6.2*12=74.4m²
ΔT=30-8=22°C
L=thickness=8cm=0.08m
t=time=16.9h=60840s
Replacing:
Explanation:
