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alukav5142 [94]
4 years ago
7

What is an isotope ?

Physics
1 answer:
Step2247 [10]4 years ago
8 0

<span>An isotope is a form of a chemical element whose atomic nucleus contains a specific number of neutrons in addition to the number of protons that distinctively defines the element. The nuclei of most atoms have neutrons as well as protons.</span>

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The same 2000 kg truck formerly traveling at 32 m/s, plows into a
kvasek [131]

Answer: |F| = 1.28 x 10⁵ N

Explanation:

an impulse results in a change of momentum

FΔt = mΔv

F = m(vf - vi)/t

F = 2000(0 - 32) / 0.5

F = -128,000

|F| = 1.28 x 10⁵ N

5 0
3 years ago
An exoplanet is in an elliptical orbit around a distant star. At its closest approach, the exoplanet is 0.540 AU from the star a
atroni [7]

Answer:

0.71121 km/s

Explanation:

v_1 = Velocity of planet initially = 54 km/s

r_1 = Distance from star = 0.54 AU

v_2 = Final velocity of planet

r_2 = Final distance from star = 41 AU

As the angular momentum of the system is conserved

mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

7 0
3 years ago
If you add a light bulb to the circuit, the filament in the bulb will resist the flow of
Leno4ka [110]

Answer:

Light and heat!

Explanation:

This is correct<3

8 0
3 years ago
Read 2 more answers
A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c
seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2

So the volume flow rate along the pipe is

\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s

We can use the similar logic to find the cross-section area at the refinery

A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2

The radius of the pipe at the refinery is:

A_r = \pi r^2

r^2 =A_r/\pi = 0.446/\pi = 0.141

r = \sqrt{0.141} = 0.377m

So the diameter is twice the radius = 0.38*2 = 0.754m

6 0
3 years ago
What are the units represent work
Dovator [93]
Work Done is Joules(J)
5 0
3 years ago
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