The solution for this problem is:
Let u denote speed.
Equating momentum before and after collision:
= 0.060 * 40 = (1.5 + 0.060) u
= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
Answer:
Explanation:
given,
charge = -5.0 μC
Electric force, F = 11 i^ N
force would a proton experience = ?
we know
we know charge of proton is equal to 1.6 x 10⁻¹⁹ C
using formula
Force experienced by the photon in the same field is equal to
Answer:
1.991 × 10^(8) N/m²
Explanation:
We are told that its volume increases by 9.05%.
Thus; (ΔV/V_o) = 9.05% = 0.0905
To find the force per unit area which is also pressure, we will use bulk modulus formula;
B = Δp(V_o/ΔV)
Making Δp the subject gives;
Δp = B(ΔV/V_o)
Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²
Thus;
Δp = 2.2 × 10^(9)[0.0905]
Δp = 1.991 × 10^(8) N/m²
We have that valence electrons poses the three characteristics stated, as
Group 14 (carbon group) are identified by 4 valence electrons.
Valence electrons of atoms are used to form bonds.
Group 14 (carbon group) are identified by 4 valence electrons.
Option A,B,C
<h3>
Properties of Valence electrons</h3>
All elements in the same group or family have the same number of valence electrons: Yes, this is true as Group 14 (carbon group) are identified by 4 valence electrons.
Valence electrons are the only subatomic particles involved in forming bonds: Yes, Valence electrons of atoms are used to form bonds.
Carbon has 4 valence electrons because it is found in group 14:
True, Group 14 (carbon group) are identified by 4 valence electrons.
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