Part A:
( 5,000 : 100 ) * 6 = 300 lit.
300 lit. * 1.066 Euros/ lit. = 318.9 Euros
1 Euro = 1.20 USD
318.9 * 1.20 = 382.68 USD
Part B :
6 lit./100 km = 0.06 lit/1 km
1 gal = 3.7853 lit.
1 mile = 1.609344 km
0.06 : 3.7853 = 0.01585
... = 0.01585 gal / 1 km / * 1.609344
= 0.0255 gal/mile
Answer:
one or more cells
Explanation:
I need to have 20 characters to submit lol
Answer:
a) F= 0,19 [N] according to problem statement
b) F = 0,19*10⁹ [N] using the right value of K
Explanation:
The force between two electric charges is according to Coulomb´s law is:
F = K * q₁*q₂ / d² where q₁ and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant K = 8,988100*10⁹ N.m²/C². The problem establishes to use K = 8,988100 N.m²/C².
NOTE: To value of is : K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹
Then:
F = 8,988100 * 1,2* 0,36 / (4,5)² [ N*m²/C² ] * [ C*C*/m²]
F = 3,882859/ 20,25 [N]
F= 0,19 [N]
The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies
Answer:At the top of the page is a transvers wave
C= crest
B= wavelingth
D= trough
A= amplatud
The next wave is a longitudinal wave
Answer:
v=39.05 m/s
Explanation:
Given that
x= 56 cm
F= 158 N
m= 58 g = 0.058 kg
Lets take spring constant = k
At the initial position,before releasing the arrow
F= k x
By putting the values
F= k x
158= 0.56 k
k=282.14 N/m
Now from energy conservation
Lets take final speed of the arrow after releasing
k x²=mv²
282.14 x 0.56² = 0.058 v²
v=39.05 m/s
