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3 years ago

Which question is a statistical question?

Mathematics

1 answer:

Sidana [21]3 years ago

4 0

Answer: Third option is correct.

Step-by-step explanation:

Statistical questions are those in which we get more than one numerical answer.

According to options,

In option 'A' how many theatres are there in my city, we get only one numerical value instead of collection of data.

In option 'B' how many students like classic movies in my class , in which we get only one numerical value.

In option 'C' how many movies do the students in my class watch in a month.

In this option we would get a collection of data i.e. more than one numerical value.

Because not every student watch same number of movies in a month.

In option 'D' again we get only one numerical value.

Hence, Third option is correct.

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A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo

levacccp [35]

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for 2 worthless stone selection),

X = 1200(1 worthless stone & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

$(^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!} \\ \\ \implies \dfrac{30*29*28!}{2!(28)!} \\ \\ \implies \dfrac{30*29}{2*1} \\ \\ \implies 435$

Thus;

$Pr (X = 0) = \dfrac{(^8_2)}{435}$

$Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\ Pr (X = 0) = 0.0644$

$P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}$

$P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}$

$P(X =1200) = \dfrac{ (8) ( 22) }{435}$

$P(X =1200) =0.4046$

$Pr (X = 2400) = \dfrac{(^{22}_2)}{435}$

$Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\ Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\ Pr (X = 2400) = 0.5310$

To find E(X):

E(X) = (0 × 0.0644) + (1200 × 0.4046) + (2400 × 0.5310)

E(X) = 0 + 485.52 + 1274.4

E(X) = 1759.92

8 0

3 years ago

I NEEEED HELP!!! please show work in answer and no blank or nonsense answers please :)

rodikova [14]

Answer:

225 pi = pi r^2 h

225 = r^2*h

225/1 = r^2

sqrt. (225) = r

r = 15

8 0

3 years ago

There are 25 students in a class. 16 of those students are boys. What percent of the class are girls?

fomenos

Answer:

36 %

Step-by-step explanation:

9 girls = 36%

25 students = 100

7 0

3 years ago

Read 2 more answers

The difference between the cost of fish and the coast of meat is no less than 150

zmey [24]

Answer:

I thought fish was another form of meat but wow!!

Step-by-step explanation:

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3 years ago

I’m sorry I’m bad at math and I need help

Natali [406]

A or B

I'm confuseddd omg

5 0

3 years ago