To do these problems, you need to multiply your (x - 3) by something to make it the same as the first number under your radical sign. For example, for the first step, I multiplied (x - 3) by -2x^2 to get (-2x^3 +6x^2). When you subtract it from the number under your radical like you would in regular long division, you can change its signs to cancel out the first number under the radical. The blocky-looking subtraction signs are ones I changed. Your final answer is (-2x^2-10x-27) with a remainder of -79.
Answer:
the answer is the graph c (3)
Step-by-step explanation:
Answer:
f(x) = x² +x -6
Step-by-step explanation:
The standard form will look like ...
f(x) = x² +bx +c
where b is the opposite of the sum of the roots, and c is their product.
f(x) = x² -(-3+2)x +(-3)(2)
f(x) = x² +x -6
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<em>Additional comment</em>
In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).
Answer:
3 times more
Step-by-step explanation: