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Answer:
The relation is reflexive as
(1,1),(2,2),(3,3)∈R
(2,1)∈R will not imply (1,2)∈R,
hence R is not symmetric
(2,1),(1,3)∈R doesn't imply (2,3)∈R, hence R is not transitive
Step-by-step explanation:
hope this helps if not let me know have a blessed day
You need to get y alone for both equations. for x-y=7, you subract x from both sides. (giving you -y = 7 - x) then, multiply the whole equation by -1 to make the y positive, which gives you y = x - 7.
here is the system in y intercept form so you can graph it easier:
*y = x - 7
*y = x + 4
Answer:
2
Step-by-step explanation:
For some angle "a", the sine and cosine are related by ...
sin(a) = cos(π/2 -a)
That is,
sin(7π/16) = cos(π/16)
sin(5π/16) = cos(3π/16)
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Then your sum becomes ...
sum = sin(π/16)² +sin(3π/16)² +cos(3π/16)² +cos(π/16)²
If we let α = π/16 and β = 3π/16, this can be written as ...
sum = (sin(α)² +cos(α)²) +(sin(β)² +cos(β)²)
sum = 1 + 1
sum = 2
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The identity sin(α)² +cos(α)² = 1 is sometimes called the Pythagorean identity.
Answer:
Bella for this to be a complete question you have to have , either two points or be given the slope of the line. Other wise there is not enough info to solve it. :/
Step-by-step explanation:
