Answer:
3y=x-1 OR y=⅓x-⅓
Step-by-step explanation:
Lets call the equation y=-3x+7 line l1
the other line passing through (4,1) l2
If two lines are perpendicular,then the product of their roots=-1
That is m(l1)×m(l2)=-1
Slope of l1=-3 therefore slope of l2=-1÷-3=⅓
Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form
y-y1=m(x-x1)
y-1=⅓(x-4)
3y-3=x-4
3y=x-4+3
3y=x-1 OR y=⅓x-⅓
Answer:
(-9+√17)/8
Step-by-step explanation:
its an example of quadratic
Answer:
Step-by-step explanation:
A system of linear equations is one which may be written in the form
a11x1 + a12x2 + · · · + a1nxn = b1 (1)
a21x1 + a22x2 + · · · + a2nxn = b2 (2)
.
am1x1 + am2x2 + · · · + amnxn = bm (m)
Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the
xi
’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of
the form constant × x
Solving Linear Systems of Equations
We now introduce, by way of several examples, the systematic procedure for solving systems of linear
equations.
Here is a system of three equations in three unknowns.
x1+ x2 + x3 = 4 (1)
x1+ 2x2 + 3x3 = 9 (2)
2x1+ 3x2 + x3 = 7 (3)
We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1
in terms of x2 and x3
x1 = 4 − x2 − x3 (1’)
1
and substituting this solution into the remaining two equations
(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5
(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1
Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1), 
in equation (2)
Differentiate both sides with respect to L:
Put it equal to zero for maxima and minima
L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.
