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Maru [420]
4 years ago
5

If two gases are present in a container, the total pressure in the container is equal to

Chemistry
2 answers:
Veronika [31]4 years ago
8 0

Answer: The correct option is (a).

Explanation:

If two gases are present in a container, the total pressure in the container is equal to the sum of the all the individual pressures exerted by the individual gases in a container.

Individual pressure exerted by the individual gas in a container is called partial pressure of that individual gas.

So, total pressure of gas in container is:

p^o=p_a+p_b

Where p^o = Total pressure exerted by the gases in the container.

p_a = Partial pressure of gas 'a'

p_b = partial pressure of gas 'b'

igor_vitrenko [27]4 years ago
7 0

The answer is a, because the question is referring to partial pressures. Partial pressures are a mere sum, no halving or doubling of anything is necessary.


So, A

Hope this helped :)

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Answer:

Answer

Explanation:

Evidence from fossils, glaciers, and complementary coastlines helps reveal how the plates once fit together. Fossils tell us when and where plants and animals once existed. ... This distribution of fossils led to theories that the southern continents were once joined in a supercontinent called Gondwana.

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Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance
ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

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Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

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Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

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Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

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Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

8 0
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vagabundo [1.1K]

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