When we balance this equation
SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)
We will get
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
Solution:
Balancing this equation
SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)
We have to balance the number of O
SnO₂(s) + H₂(g) ⇄ Sn(s) + 2H₂O(g)
We have to balance the number of H
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
We will get the balanced equation
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [Sn(s) + H₂O(g)] / [SnO₂(s) + H₂(g)]
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