Answer:
fraction of vacancies for this metal FV = 1.918*10⁻⁴
Explanation:
Given:
The number of vacancies per unit volume => ( Nv = 1*10²⁵ m⁻³ )
But we know that Avogrado's constant NA = 6.022*10²³ atoms/mol
Density of the material is given in g/cm3 we need to convert it to g/m³
Density of material ( p ) in g/m³ :
To convert we know that
1 g/cm³ = 1000000 g/m³ then
7.40 * ( 1000000 ) = 7.40*10⁶ g/m³
So, Density of material ( p ) in g/m³ = 7.40*10⁶ g/m³
Given Atomic mass = 85.5 g/mol
To Calculate the number of atomic sites per unit volume , we will use the below formula by substituting those values above
N = NA * p / A
N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5
N = 4.45*10³⁰ / 85.5
N = 5.212*10²⁸ atoms/m³
We can now Calculate the fraction of vacancies using the formula below;
Fv = Nv / N
Fv = 1*10²⁵ / 5.212*10²⁸
fraction of vacancies for this metal at 600c.= 1.918*10⁻⁴
Answer:
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Reproduction is defined as the production of individuals of the same species, that is the next generation of the species.
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There are basically two types of reproduction - asexual and sexual.
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Asexual reproduction involves only one parent and the offspring is
genetically similar to the parent ...
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The different types of asexual reproduction are fission, budding, fragmentation, spore formation and vegetative propagation.
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Sexual reproduction is a type of reproduction that involves a complex life cycle in which a gamete (such as a sperm or egg cell) with a single set of chromosomes combines with another to produce a organism composed of cells with two sets of chromosomes .
Asexual reproduction is a type of reproduction which does not involve the fusion of gametes or change in the number of chromosomes. The offspring that arise by asexual reproduction from a single cell or from a multicellular organism inherit the genes of that parent.
Explanation:
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K
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Since the blood moves from the body to the right atrium to the right ventricle
Answer:
the fastest would be gas, liquid would be in the middle and solid would be the slowest
Explanation:
Answer:
They give off their own light energy
Explanation:
I'm taking astronomy and I answered this questions not too long ago
