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vekshin1
4 years ago
13

♡

Chemistry
1 answer:
Oksi-84 [34.3K]4 years ago
4 0

Your question has been heard loud and clear.

Both scientific laws and scientific theories are not based on hypothesis.

Because , scientific laws are proven and so they are real not hypothetical.

Whereas scientifc theories can be hypothetical.

Thank you

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Solve for ‘x’: 12(x-7)+3(2x+2)=50x-2
Alex Ar [27]

Answer:

Explanation:

Hi there!

12(x-7) = 12x -84

3(2x+2) = 6x+6

Total 18x-78

18x-78 = 50x-2

-78= 32x-2

-76= 32x

19/8 =x

Hope you understand

Have a nice day,

Wolfiex.

5 0
4 years ago
If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the
navik [9.2K]

1.199 M is the concentration of KCI in the resulting solution.

<h3 /><h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

Moles = \frac{mass}{molar \;mass}

Moles = \frac{44.7 g}{74.5513 g/mol}

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Molality = \frac{0.599 moles}{0.5 liter}

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

6 0
2 years ago
Assuming constant pressure and temperature, how many moles of gas have been added to the initial 3 moles of gas when the volume
puteri [66]
The answer is 3 moles
3 0
3 years ago
Can beans grow inside water
fredd [130]
No, They need something to hold on to, such as dirt
8 0
4 years ago
Read 2 more answers
copper (1) oxide Cu2O is reduced to metallic copper by heating in a stream of hydrogen gas. what mass of water is produced when
dusya [7]
Answer:
             1.41 g of H₂O

Solution:
The equation for given reaction is as follow,

                              Cu₂O  +  H₂     →     2 Cu  +  H₂O

According to equation,

      127 g (2 mole) Cu is produced along with  =  18 g (1 mole) of H₂O
So,
                      10 g Cu produced will generate  =  X g of H₂O

Solving for X,
                     X  =  (18 g × 10 g) ÷ 127 g

                     X  =  1.41 g of H₂O
4 0
3 years ago
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