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3 years ago

how many moles of cesium carbonate will be produced when 5.34 moles of cesium reacts with iron iii carbonate

Chemistry

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

2.67 moles of Cs₂CO₃

Explanation:

The balance chemical equation for given single replacement reaction is;

6 Cs + Fe₂(CO₃)₃ → 3 Cs₂CO₃ + 2 Fe

According to equation,

6 moles of Cs produced = 3 moles of Cs₂CO₃

So,

5.34 moles of Cs will produce = X moles of Cs

Solving for X,

X = 5.34 mol × 3 mol / 6 mol

X = 2.67 moles of Cs₂CO₃

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3 years ago

hat is the percentage of water in the following compound? Answer using three significant figures. Sodium carbonate decahydrate,

BigorU [14]

You need to find the whole molar mass of the compound using the periodic table to add the values.

Na2CO3= (2 x 23.0) + 12.0 + (3 x 16.0)= 106 g/mol
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3 years ago

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7 0

3 years ago

Read 2 more answers

Balance each of the following redox reactions occurring in basic solution.MnO−4(aq)+Br−(aq)→MnO2(s)+BrO−3(aq)Express your answer

Ahat [919]

Answer : The balanced chemical equation is,

$2MnO_4^-(aq)+Br^-(aq)+H_2O(l)\rightarrow 2MnO_2(s)+BrO_3^-(aq)+2OH^-(aq)$

Explanation :

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.
Now balance the main atoms in the reaction.
Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion $(OH^-)$ at that side where the less number of hydrogen are present.
Now balance the charge.

The half reactions in the basic solution are :

Reduction : $MnO_4^-(aq)+2H_2O(l)+3e^-\rightarrow MnO_2(s)+4OH^-(aq)$ ......(1)

Oxidation : $Br^-(aq)+6OH^-(aq)\rightarrow BrO_3^-(aq)+3H_2O(l)+6e^-$ .......(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2MnO_4^-(aq)+Br^-(aq)+H_2O(l)\rightarrow 2MnO_2(s)+BrO_3^-(aq)+2OH^-(aq)$

8 0

3 years ago

How many moles are there in 78.3g of CO2?

oksano4ka [1.4K]

The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2

4 0

3 years ago