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deff fn [24]
3 years ago
10

NEED HELP ASAP PLS

Chemistry
1 answer:
densk [106]3 years ago
5 0

Answer:

31.60% phosphorus

Explanation:

To find the percent by mass, you first calculate the total mass and then the mass of phosphorus, and finally divide phosphorus mass by total.

Phosphorus mass: the molar mass of P is 30.97 g/mol, and since there's 1 mole of P, we just have 30.97 g.

Total mass: we add all the molar masses of the components together.

We have 3 moles of H, so we multiply 3 by 1.008 g/mol = 3.024 g H.

We already calculated the mass of phosphorus: 30.97 g P.

We have 4 moles of O, so we multiply 4 by 16.00 g/mol = 64.00 g O.

The total is then the sum: 3.024 + 30.97 + 64.00 = 97.994 g ≈ 97.99 g

Now, to find the percentage, we take 30.97 g P and divide by 97.99:

30.97/97.99 ≈ 0.3160 ⇒ 31.60% P

Thus, the answer is 31.60% phosphorus.

Hope this helps!

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Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

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The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

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Answer:

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3 years ago
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Can anyone help me on this please?
Bad White [126]
This question is testing to see how well you understand the "half-life" of radioactive elements, and how well you can manipulate and dance around them.  This is not an easy question.

The idea is that the "half-life" is a certain amount of time.  It's the time it takes for 'half' of the atoms in any sample of that particular unstable element to 'decay' ... their nuclei die, fall apart, and turn into nuclei of other elements.

Look over the table.  There are 4,500 atoms of this radioactive substance when the time is 12,000 seconds, and there are 2,250 atoms of it left when the time is ' y ' seconds.  Gosh ... 2,250 is exactly half of 4,500 !  So the length of time from 12,000 seconds until ' y ' is the half life of this substance !  But how can we find the length of the half-life ? ? ?

Maybe we can figure it out from other information in the table !

Here's what I found:

Do you see the time when there were 3,600 atoms of it ? 
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... After one half-life, there were 1,800 atoms left.
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... After another half-life, there were 450 atoms left. 

==>  450 is in the table !  That's at 95,000 seconds.

So the length of time from 20,000 seconds until 95,000 seconds
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The length of time is (95,000 - 20,000) = 75,000 sec

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Divide each side by 3 :   1 half life = 25,000 seconds

There it is !  THAT's the number we need.  We can answer the question now.

==> 2,250 atoms is half of 4,500 atoms.

==> ' y ' is one half-life later than 12,000 seconds

==> ' y ' = 12,000 + 25,000

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Check: 
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