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skelet666 [1.2K]
4 years ago
10

The redshift of the galaxies is correctly interpreted as

Physics
2 answers:
pickupchik [31]4 years ago
5 0
Doppler shift due to random motion of galaxies ,an aging of light as gravity weakens with time ,the difference in temperature and star formation in old and new galaxies
DerKrebs [107]4 years ago
5 0

It's simply showing red-shift on a big, big stage. The Big Bang explosion was so massive that most things we can see in the universe are still moving away from us. Some things nearby -- planets or stars -- are moving closer. So, cosmological red-shift means that light stretches as space expands. This is one of the defining proofs for the The Big Bang Theory as well as that the Universe is expanding.

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A conducting spherical shell with inner radius ‘a’ and outer radius ‘b’ has a positive charge Q located at its center. The total
kifflom [539]

Answer:deeeznuts

Explanation:

4 0
3 years ago
Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'
uranmaximum [27]

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.174 ft/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-182.218^2}{2\times 3.6}\\\Rightarrow a=-4611.58\ ft/s^2

Magnitude of acceleration while stopping is 4611.58 ft/s²

8 0
3 years ago
A loop of wire is placed in a uniform magnetic field. Let ø be the angle between the direction of b and the normal. At which val
zaharov [31]

Answer:

B. 0 degrees

Explanation:

The magnetic flux through a certain area enclosed by a loop of wire immersed in a region with magnetic field is given by:

\Phi = B A cos \theta

where

B is the strength of the magnetic field

A is the area enclosed by the coil

\theta is the angle between the direction of the magnetic field and the direction of the normal to the coil

From the equation above, we see that the magnetic flux is maximum when

cos \theta=1

So when the field is parallel to the normal to the coil (so, when it is perpendicular to the coil), therefore when:

\theta=0^{\circ}

So, the correct option is

B. 0 degrees

5 0
4 years ago
3) If a ball launched at an angle of 10.0 degrees above horizontal from an initial height of 1.50 meters has a final horizontal
Irina-Kira [14]

Answer:

35.6 m

Explanation:

3 0
4 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
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