A uranium-235 atom<span> absorbs a neutron and fissions into two new </span>atoms<span> (fission fragments), releasing three new neutrons and some binding energy. ... Several heavy elements, such as uranium, thorium, and plutonium, undergo both spontaneous fission, a form of radioactive decay and induced fission, a form of </span>nuclear<span> reaction.</span>
Answer:
a) 145.6kgm^2
b) 158.4kg-m^2/s
c) 0.76rads/s
Explanation:
Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation
(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and
(c) the angular speed of the merry-go-round and child after the child has jumped on.
a) From I = MK^2
I = (160Kg)(0.91m)^2
I = 145.6kgm^2
b) The magnitude of the angular momentum is given by:
L= r × p The raduis and momentum are perpendicular.
L = r × mc
L = (1.20m)(44.0kg)(3.0m/s)
L = 158.4kg-m^2/s
c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:
L = Iw
158.4kgm^2/s = [145kgm^2 + ( 44.0kg)(1.20)^2]
w = 158.6/208.96
w = 0.76rad/s
Answer : The correct option is, (D) 278 K
Explanation :
We are given temperature 
.
Now the conversion factor used for the temperature is,
where, K is kelvin and 
is Celsius.
Now put the value of temperature, we get
Therefore, the temperature 278 K is equal to the
Answer:
5 m/s2, left
Explanation:
We can solve the problem by applying Newton's second law of motion, which states that:
where:
is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, we have:
(to the left) is the net force on the object
m = 2.0 kg is the mass
So, the acceleration is:
in the same direction as the force (left).
