Please indicate how long each bar is in centimeters and millimeters.

The boy moving down the hill posses what energy?

elena-s [515]

Answer: Kinetic energy

Explanation:

Kinetic energy and potential energy can change forms. For example, the car moving up the hill is kinetic energy

6 0

2 years ago

Read 2 more answers

A large rocket has a mass of 2.00×10⁶ kg at takeoff, and its engines produce a thrust of 3.50×10⁷ N. Find its initial accelerati

Kazeer [188]

Answer:

17.5 m/s²

1.90476 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Force

$F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{3.5\times 10^7}{2\times 10^6}\\\Rightarrow a=17.5\ m/s^2$

Initial acceleration of the rocket is 17.5 m/s²

$v=u+at\\\Rightarrow \frac{120}{3.6}=0+17.5t\\\Rightarrow t=\frac{\frac{120}{3.6}}{17.5}=1.90476\ s$

Time taken by the rocket to reach 120 km/h is 1.90476 seconds

Change in the velocity of a rocket is given by the Tsiolkovsky rocket equation

$\Delta v=v_{e}\ln \frac{m_0}{m_f}$

where,

$m_0$ = Initial mass of rocket with fuel

$m_f$ = Final mass of rocket without fuel

$v_e$ = Exhaust gas velocity

Hence, the change in velocity increases as the mass decreases which changes the acceleration

4 0

2 years ago

What is required for the maximum high tide to occur?.

daser333 [38]

Answer:

Tides are very long waves that move across the oceans. They are caused by the gravitational forces exerted on the earth by the moon, and to a lesser extent, the sun. ... Because the gravitational pull of the moon is weaker on the far side of the Earth, inertia wins, the ocean bulges out and high tide occurs.

Explanation:

4 0

2 years ago

Suppose you studied the velocity of a cheetah overtime after it starts running to chase an deer. After the linear fit, a spreads

EastWind [94]

Explanation:

While studying the velocity of a cheetah over time in a spreadsheet program is given by :

y = 2.2 x + 1.2 ...(1)

We know that,

v=v₀+at ...(2)

v₀ is velocity when t = 0, v is velocity after time t, a is acceleration and t is time.

If we consider time t on x-axis and v on y axis, then only we can draw a plot of equation (2). On comparing equation (1) and (2) we get :

a = 2.2 (but it is not correct as we don't know about axes).

Hence, the correct option is (a) "We cant tell without knowing what was plotted on the horizontal and vertical axes"

6 0

2 years ago

A spring with a spring constant of 25.1 N/m is attached to different masses, and the system is set in motion. What is its period

Ratling [72]

1) 2.17 s

The period of a mass-spring oscillating system is given by

$T=2 \pi \sqrt{\frac{m}{k}}$

where k is the spring constant and m is the mass attached to the spring. In this problem, we have

k = 25.1 N/m

m = 3.0 kg

Substituting into the equation, we find

$T=2 \pi \sqrt{\frac{3.0 kg}{25.1 N/m}}=2.17 s$

2) 0.46 Hz

The frequency of the oscillating system is equal to the reciprocal of the period:

$f=\frac{1}{T}$

Therefore, by substituting T=2.17 s, we find:

$f=\frac{1}{T}=\frac{1}{2.17 s}=0.46 Hz$

3) 0.13 s

As before, the period of a mass-spring oscillating system is given by

$T=2 \pi \sqrt{\frac{m}{k}}$

where k is the spring constant and m is the mass attached to the spring. In this part of the problem, we have

k = 25.1 N/m

m = 11 g = 0.011 kg

Substituting into the equation, we find

$T=2 \pi \sqrt{\frac{0.011 kg}{25.1 N/m}}=0.13 s$

4) 7.69 Hz

The frequency of the oscillating system is equal to the reciprocal of the period:

$f=\frac{1}{T}$

Therefore, by substituting T=0.13 s, we find:

$f=\frac{1}{T}=\frac{1}{0.13 s}=7.69 Hz$

5) 1.59 s

Again, the formula for the period of a mass-spring oscillating system is given by

$T=2 \pi \sqrt{\frac{m}{k}}$

In this part of the problem, we have

k = 25.1 N/m

m = 1.6 kg

Substituting into the equation, we find

$T=2 \pi \sqrt{\frac{1.6 kg}{25.1 N/m}}=1.59 s$

6 0

2 years ago