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Lesechka [4]
3 years ago
13

Suppose that you find the volume of all the oceans to be 1.4×109km3 in a reference book. To find the mass, you can use the densi

ty of water, also found in this reference book, but first you must convert the volume to cubic meters. What is this volume in cubic meters?
Physics
2 answers:
Licemer1 [7]3 years ago
8 0

Answer:

Explanation:

Volume of ocean = 1.4×10^9 km3

To m^3,

1.4 × 10^9 km^3 × (1000 m)^3/(1 km)^3

= 1.4 × 10^18 m^3.

Density of water = 1000 kg/m3

Mass = density × volume

= 1000 × 1.4 × 10^18

= 1.4 × 10^21 kg.

PSYCHO15rus [73]3 years ago
4 0

Answer:

V = 1.4\times 10^{18}\,m^{3},m = 1.435\times 10^{21}\,kg

Explanation:

The volume of all oceans is:

V = (1.4\times 10^{9}\,km^{3})\cdot (\frac{1\times 10^{9}\,m^{3}}{1\,km^{3}} )

V = 1.4\times 10^{18}\,m^{3}

Ocean water has a density of 1025\,\frac{kg}{m^{3}}, the mass of all oceans is:

m = (1025\,\frac{kg}{m^{3}} )\cdot (1.4\times 10^{18}\,m^{3})

m = 1.435\times 10^{21}\,kg

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wlad13 [49]

Answer:

Power output = 2\times 10^4\ W

Explanation:

Given:

Mass of the elevator is, m=1000\ kg

Height to which it is raised is, h=10\ m

Acceleration due to gravity is, g=10\ m/s^2(Approximately)

Time taken by the motor to raise the elevator is, t=5.0\ s

Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.

Increase in gravitational potential energy is given as:

\Delta U=mgh=(1000)(10)(10)=10\times 10^4\ J

Therefore, work done by motor is, W=10\times 10^4\ J

Now, we know that, power is work done in unit time. So, power output is given as:

Power=\frac{W}{t}\\\\Power=\frac{10\times 10^4\ J}{5.0\ s}\\\\Power=2\times 10^4\ J/s\\\\Power=2\times 10^4\ W..........[1 W = 1\ J/s]

Therefore, the power output of the first motor is 2\times 10^4\ W

7 0
3 years ago
The wavelengths of visible light vary from about 300 nm to 700 nm. What is the range of frequencies of visible light in a vacuum
exis [7]

The range of frequencies  of visible light in a vacuum is mathematically given as

Fmin=4.19*10^14Hz  to Fmax=1*10^15Hz

<h3>What is the range of frequencies of visible light in a vacuum?</h3>

Question Parameters:

The wavelengths of visible light vary from about 300 nm to 700 nm.

Generally, the equation for the frequency   is mathematically given as

F=C/\lambda

Therefore

For Fmax

Fmax=\frac{300*10^8}{3*10^9}

Fmax=1*10^15Hz

Where

Fmin=\frac{3*10^8}{700*10^9}

Fmin=4.19*10^14Hz

For more information on Wave

brainly.com/question/3004869

6 0
2 years ago
Raul wants to increase his upper body and cardiovascular strength. He plans to go to the gym and use his backyard swimming pool
Mkey [24]

Answer: An exercise, activity, or workout that targets a specific training need Progression - Gradually increasing your skill level and ability over time Overload -Working your body harder than usual to improve how it functions Reversibility - Losing what you have gained by taking time off Tedium - getting bored by doing the same thing

Explanation:

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3 years ago
What is an earthquake?
mart [117]
An earthquake is when two tectonic plate merge and one snaps up suddenly, causing the plate to shake violently until it settles back into place. hope i helped :3
6 0
3 years ago
During a tennis serve, a racket is given an angular acceleration of magnitude 150 rad/s^2. At the top of the serve, the racket h
QveST [7]

Answer:

270 m/s²

Explanation:

Given:

α = 150 rad/s²

ω = 12.0 rad/s

r = 1.30 m

Find:

a

The acceleration will have two components: a radial component and a tangential component.

The tangential component is:

at = αr

at = (150 rad/s²)(1.30 m)

at = 195 m/s²

The radial component is:

ar = v² / r

ar = ω² r

ar = (12.0 rad/s)² (1.30 m)

ar = 187.2 m/s²

So the magnitude of the total acceleration is:

a² = at² + ar²

a² = (195 m/s²)² + (187.2 m/s²)²

a = 270 m/s²

3 0
3 years ago
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