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Lesechka [4]
3 years ago
13

Suppose that you find the volume of all the oceans to be 1.4×109km3 in a reference book. To find the mass, you can use the densi

ty of water, also found in this reference book, but first you must convert the volume to cubic meters. What is this volume in cubic meters?
Physics
2 answers:
Licemer1 [7]3 years ago
8 0

Answer:

Explanation:

Volume of ocean = 1.4×10^9 km3

To m^3,

1.4 × 10^9 km^3 × (1000 m)^3/(1 km)^3

= 1.4 × 10^18 m^3.

Density of water = 1000 kg/m3

Mass = density × volume

= 1000 × 1.4 × 10^18

= 1.4 × 10^21 kg.

PSYCHO15rus [73]3 years ago
4 0

Answer:

V = 1.4\times 10^{18}\,m^{3},m = 1.435\times 10^{21}\,kg

Explanation:

The volume of all oceans is:

V = (1.4\times 10^{9}\,km^{3})\cdot (\frac{1\times 10^{9}\,m^{3}}{1\,km^{3}} )

V = 1.4\times 10^{18}\,m^{3}

Ocean water has a density of 1025\,\frac{kg}{m^{3}}, the mass of all oceans is:

m = (1025\,\frac{kg}{m^{3}} )\cdot (1.4\times 10^{18}\,m^{3})

m = 1.435\times 10^{21}\,kg

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3 years ago
A truck with a heavy load has a total mass of 7100 kg. It is climbing a 15∘ incline at a steady 15 m/s when, unfortunately, the
Andrej [43]

Answer:

The load has a mass of 2636.8 kg

Explanation:

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Mass of load = m2 kg

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Step 2:

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T = (m1+m2)*g*sinθ

⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes  m1*gsinθ .

Resultant force on truck is F = T – m1*gsinθ  

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This gives the equation:

T – m1*gsinθ = m1*a  

T = m1(a + gsinθ)

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(m1+m2)*g*sinθ = m1*(a + gsinθ)

m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ

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Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:

m2*g*sinθ = (7100 – m2)*a

m2*g*sinθ = 7100a – m2a

m2*gsinθ + m2*a = 7100a

m2* (gsinθ + a) = 7100a

m2 = 7100a/(gsinθ  + a)

m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)

m2 = 2636.8 kg

The load has a mass of 2636.8 kg

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