Does anybody know how to do this
1 answer:
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Answer:
- ∠R = 56°
- ∠Q = 90°
- ∠S = 34°
Step-by-step explanation:
The given triangle is a right angled triangle.
So, the angles in the triangle are :
- 90°
- (2x + 38)°
- (5x - 11)°
Solving according to <u>angle sum property</u>,
Sum of all angles in a triangle is 180°
90° + (2x + 38)° + (5x - 11)° = 180°
117° + 7x = 180°
7x = 180° - 117°
7x = 63°
x = 9
Angles =
2(9) + 38
56°
5(9) - 11
34°
- ∠R = 56°
- ∠Q = 90°
- ∠S = 34°
The angles are 56°, 90° and 34°.
The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
then the discontinuity point is at 
.
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are