The volume of iron is obtained from the density formula (density= mass/ volume) given the density and mass. In this case, 3,880 grams of iron and a density of 7.86 g/ml are given. The volume obtained from formula is 493.64 ml or 4.94 dL.
Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g
<h3>Avogadro's hypothesis </h3>
6.02×10²³ atoms = 1 mole of arsenic
But
1 mole of arsenic = 75 g
Thus, we can say that:
6.02×10²³ atoms = 75 g of arsenic
<h3>How to determine the mass that contains 1.23×10²⁰ atoms</h3>
6.02×10²³ atoms = 75 g of arsenic
Therefore,
1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)
1.23×10²⁰ atoms = 0.0153 g of arsenic
Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic
Learn more about Avogadro's number:
brainly.com/question/26141731
Explanation:
Its ok you got this. Grab a calculator, divide the first number by the second number for each problem. And then bam, density.
At stp the volume is 22.4 L .
hope this helps!