9514 1404 393
Answer:
(x, y, z) = (-1, 0, -3)
Step-by-step explanation:
We notice that the coefficients of z are such that elimination of the z term from the equations is made easy.
Adding equations 1 and 2:
(2x -3y -2z) +(x +3y +2z) = (4) +(-7)
3x = -3
x = -1
Adding equations 2 and 3:
(x +3y +2z) +(-4x -4y -2z) = (-7) +(10)
-3x -y = 3
Substituting for x, we get ...
(-3)(-1) -y = 3
0 = y . . . . . . . . . . . add y-3 to both sides
Then z can be found from any equation. Substituting for x and y in the second equation gives ...
-1 +2z = -7
2z = -6 . . . . . add 1
z = -3 . . . . . .divide by 2
The solution is (x, y, z) = (-1, 0, -3).
<h3>
Answer: B) real number</h3>
Explanation:
Something like 3.5 = 7/2 is a rational number because its a fraction of two integers.
While on the other hand, the constant pi = 3.14159... is irrational because we cannot write pi as a fraction of two integers. We can get approximations like 22/7, but not a perfect exact match.
Both types of numbers, rational and irrational, are under the umbrella of the real number system. Any real number is a string of decimal digits. Sometimes it might be a whole number, but fractional values can be included as well. The decimal number may terminate, or it may repeat, or it may go on forever without a pattern.
In short, any number you can think of is a real number assuming your teacher hasn't covered complex numbers (or imaginary numbers) just yet.
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).
Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is = 
g/L
Outgoing rate = 
Integrating both sides
[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram
Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get
Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
50
Step-by-step explanation:
