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3 years ago

A spinner has five sections, labeled A, B, C, D, and E. The spinner is spun 84 times, and the results are recorded in the table.

Mathematics

1 answer:

Naddika [18.5K]3 years ago

4 0

$|\Omega|=84\\ |A|=14\\\\ P(A)=\dfrac{14}{84}=\dfrac{1}{6}\approx17\%$

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Sergio039 [100]

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3 years ago

Read 2 more answers

the lenght of a rectangle is 2 cm less than 7 times the width. the perimeter is 60 cm . find the width and lenght

vampirchik [111]

First, you want to establish your equations.

L=7W-2
P=60

This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.

60=2(7W-2+W)

Now that we only have 1 variable, we can solve.

First, distribute the 2.
60=14W-4+2W

Next, combine like terms.

60=16W-4

Then, add four to both sides.

64=16W

Lastly, divide both sides by 16

W=4

To find the length, we plug in our width.

7W-2

7(4)-2

28-2

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3 years ago

Members of the cooking club would like to learn how to make peach ice cream. There are 14 people in the club. Each member will n

ohaa [14]

Answer:

Step-by-step explanation:

Total members = 14

Each member:

Peaches = 3

Pint of cream = 1

Cost

Peaches = x cent

Pint of cream = 46 cent

46 cent = $0.46

Cost per member = 3(x cent) + 0.46

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Total cost for all members = 14(3x cent + 0.46)

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3 years ago

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

Lostsunrise [7]

Answer: $5.7\ cm$

Step-by-step explanation:

Given

Rectangle has an area of $19.38\ cm^2$

Suppose rectangle length and width are $l$ and $w$

If each side is increased by $1.50\ cm$

Area becomes $A_2=35.28\ cm^2$

We can write

$\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)$

Substitute the value of width from (ii) in equation (i)

$\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7$

Width corresponding to these lengths

$w=5.7,\ 3.4$

Therfore, we can write the length of the longer side is $5.7\ cm$

8 0

3 years ago