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Ronch [10]
3 years ago
11

A spinner has five sections, labeled A, B, C, D, and E. The spinner is spun 84 times, and the results are recorded in the table.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

|\Omega|=84\\ |A|=14\\\\ P(A)=\dfrac{14}{84}=\dfrac{1}{6}\approx17\%

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A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
MA_775_DIABLO [31]

Answer:

<h2>The area of the pitch in an acre is  1.32 acre</h2>

Step-by-step explanation:

This problem requires to test our understanding of unit conversion, and we are expected to present our answer in an acre

first, let us convert from the yard to feet

given that the dimension of the pitch is

120 yards by

53.333 yard

1 yard is 3 foot

120 yards will give x

cross multiply we have

x1= 120*3

x1= 360 feet

also the second dimension is

x2= 53.333*3

x2= 159.999

x2= 159.999 feet

the area of the pitch is

area= 159.999*360

area= 57599.64 ft^2

Note: an acre is a unit for land area (1 acre=43560 ft^2)

if 1 acre = 43560 ft^2

x acre =  57599.64 ft^2

cross multiply we have

x acre =  57599.64/43560

x acre = 1.32 acre

5 0
3 years ago
Please help ASAP will give brainliest
umka21 [38]

Answer:

B and E

Step-by-step explanation:

Hope it helps

4 0
4 years ago
Read 2 more answers
The blueprint scale is 1 inch : 9 feet if the gym's area is 60 square inches on the blueprint, what is the actual square footage
WITCHER [35]

Answer:

4860 ft^2

Step-by-step explanation:

9 feet is represented by 1 inch.

● 9 => 1

Square both sides

● 81 => 1

So a 81 ft^2 square is represented by a 1 in^2 square (picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

The gym's area in the blueprint is 60 in^2

That 60 1in^2 squares.

● 1 => 81

● 1×60 => 81×60

We have multiplied both sides by 60

● 60 => 4860

So the original are is 4860 ft^2

4 0
3 years ago
Read 2 more answers
el perimetro de un terreno rectangular es de 170m y su area es de 170^2hallar la medida de sus lados con ecuacion cuadratica
Blizzard [7]

Answer:

Acá tenemos un sistema de ecuaciones.

El perímetro de un rectángulo es:

2*A + 2*L = 170m

donde A es el ancho y L es el largo.

Y el área del rectángulo es:

A*L = 170m^2.

Entonces, el primer paso es aislar una de las variables en una de las ecuaciones, yo voy a aislar A en la segunda:

A = 170m^2/L.

Ahora reemplazo eso en la primera ecuación y la resuelvo para L.

2*( 170m^2/L.) + 2*L = 170m.

340m^2 + 2*L^2 = 170m*L

ahora tenemos una ecuación cuadrática:

2*L^2 - 170m*L + 340m^2 = 0.

Las soluciones se pueden obtener usando la formula de Bhaskara:

L = \frac{+170 +- \sqrt{170^2 -4*340*2}  }{2*2} = \frac{170 +-161.8}{4}

Entonces las soluciones son:

L = (170 + 161.8)/4 = 82.95m

L = (170 - 161.8)/4 = 4.1m

Entonces, si tomamos L = 82.95m, tenemos A = 4.1 m

y el área es:

A*L = 4.1m*82.95m = 170m^2

3 0
3 years ago
Plzzzzz help me with this math due soon!!
Daniel [21]

Answer:

C

Step-by-step explanation:

It crosses two points and its on the positive side so it'll be a positive 4 and 0

3 0
3 years ago
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