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3 years ago

Simplify each radical expression. √8+√28

2 answers:

8 0

Solutions

$\sqrt{8}+ \sqrt{28} 

Find the number that is multiplied by 4 and is equal to 8 and 28. 

= \sqrt{4*2} + \sqrt{4*7} 

 \sqrt[2]{2} + \sqrt[2]{7}$

dusya [7]3 years ago

4 0

$\sqrt{8} + \sqrt{28}$
= $\sqrt{4*2} + \sqrt{4*7}$
=2 $\sqrt{2} +2 \sqrt{7}$

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