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3 years ago

Please help me with number 2

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

Step-by-step explanation:

Since the firm was hired to create a box kind of shape, the length, width and height will be the same

i.e volume= L*W*H= (L*L*L)= $L^3$

$18=L^3\\L= \sqrt{18} \\L= 3 cm$

hence the dimension is

If the volume must be exactly $18cm^3$ the dimension must be

length= 3 cm,

width = 3 cm and

height = 3 cm

The set of dimension if the company is to use the least materials is

length= 3 cm,

width = 3 cm and

height = 3 cm

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Which of the following ordered pairs is a solution to the equation 2x+6y=−6 ?

pogonyaev

(-3, 2) -6+12=-6
(3, -2) 6-12=-6

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What is the value of 4^-2? Leave your answer in fraction form of necessary.

valkas [14]

Answer:

1/16

Step-by-step explanation:

We know that a^ -b is equal to 1 / a^b

That means

4^-2 = 1/ 4^2 = 1/16

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Find the lengths of the sides of the triangle PQR. P(2, −3, −4), Q(8, 0, 2), R(11, −6, −4) |PQ| = Incorrect: Your answer is inco

Aloiza [94]

Answer:

the length PQ is 9 units,the length QR is 9 units,the length PR is 9.48 units,the triangle is not a right triangle,this is a isosceles triangle

Step-by-step explanation:

Hello, I think I can help you with this

If you know two points, the distance between then its given by:

$P1(x_{1},y_{1},z_{1} ) \\P2(x_{2},y_{2},z_{2})\\\\d=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}+(z_{2}-z_{1} )^{2} }$

Step 1

use the formula to find the length PQ

Let

P1=P=P(2, −3, −4)

P2=Q=Q(8, 0, 2)

$d=\sqrt{(8-2)^{2} +(0-(-3))^{2}+(2-(-4))^{2}} \\ d=\sqrt{(6)^{2} +(3)^{2}+(6 )^{2}}} \\d=\sqrt{36+9+36}\\d=\sqrt{81} \\d=9\\$

the length PQ is 9 units

Step 2

use the formula to find the length QR

Let

P1=Q=Q(8, 0, 2)

P2=R= R(11, −6, −4)

$d=\sqrt{(11-8)^{2} +(6-0))^{2}+(-4-2 )^{2}} \\\\\\d=\sqrt{(3)^{2} +(6)^{2}+(-6 )^{2}}} \\d=\sqrt{9+36+36}\\d=\sqrt{81} \\d=9\\$

the length QR is 9 units

Step 3

use the formula to find the length PR

Let

P1=P(2, −3, −4)

P2=R= R(11, −6, −4)

$d=\sqrt{(11-2)^{2} +(-6-(-3)))^{2}+(-4-4 )^{2}} \\\\\\d=\sqrt{(9)^{2} +(-6+3)^{2}+(-4-(-4) )^{2}}} \\d=\sqrt{81+9+0}\\d=\sqrt{90} \\d=9.48\\$

the length PR is 9.48 units

Step 4

is it a right triangle?

you can check this by using:

$side^{2} +side^{2}=hypotenuse ^{2}$

Let

side 1=side 2= 9

hypotenuse = 9.48

Put the values into the equation

$9^{2} +9^{2} =9.48^{2}\\ 81+81=90\\162=90,false$

Hence, the triangle is not a right triangle

Step 5

is it an isosceles triangle?

In geometry, an isosceles triangle is a type of triangle that has two sides of equal length.

Now side PQ=QR, so this is a isosceles triangle

Have a great day

3 0

3 years ago

Free Brainiest Fellows

pychu [463]

Answer:

Explanation: An isosceles triangle is a triangle in which two of the three sides are the same length, or two of the three angles are the same degree.

Step-by-step explanation:

4 0

3 years ago

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What is the value of x?????

ioda

x=4, because 10+(4*2)=10+8=18 and since it is a rectangle the sides are the same.

5 0

3 years ago