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Luden [163]
3 years ago
15

Three piles of 7 beans each are to be made from 10 red, 5 yellow, and 6 green beans. If all of the beans must be used and each s

tack must contain at least one bean of each color, then what is the maximum number of red beans that can be put in one of the stacks?
Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer:

The maximum number of red beans that can be put in one of the stacks is 5.

Step-by-step explanation:

First, Every pile is made with 7 beans, but they need to have at least one bean of each color, so we need to include in the pile minimum one yellow bean and one green bean. If we make a stack with this condition, the stack is going to have: 1 yellow bean, 1 green bean, and 5 red beans.

Additionally, it is necessary to know if there are enough red beans for the other piles. In this case, we have 10 red beans so if we have 5 red beans in one stack, the other two stacks have enough red beans to fulfill with the condition to have at least one red bean.

So, the maximum number of red beans that can be put in one of the stacks is 5.

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I beg for someone. I need a maximum, minimum, domain, and range of polynomial:
elena-s [515]

Answer:

  • domain: all real numbers, (-∞, ∞)
  • range: all real numbers, (-∞, ∞)
  • maximum: +∞
  • minimum: -∞

Step-by-step explanation:

The function is an odd-degree polynomial. The domain and range of any odd-degree polynomial is (-∞, +∞). It has no finite maximum or minimum.

There are 3 local maxima, and 3 local minima. The ones that are non-zero are irrational. Those are about -150.018, -580.455, and 578.545. If you're seriously expected to solve for these values, no doubt you have been given a method for doing so. Use that method.

These local extreme values are reported by the Desmos on-line graphing calculator.

3 0
3 years ago
What is 6668 divided by 44
cupoosta [38]
The anwer plus working is 6668/4=151.55
5 0
3 years ago
X2 – 5x + 6 = 0 solve.
Strike441 [17]
When you factor you get (x-2)(x-3)=0 then x=2 and x=3
4 0
3 years ago
You have been given the task of transporting 3,000 apples 1,000 miles from Appleland to Bananaville. Your truck can carry 1,000
chubhunter [2.5K]
If the truck can carry 1000 apples at a time, Bananaville is 1000 miles away from Appleland and you pay one apple per mile, then it's impossible to deliver any apple to Bananaville, because on 1000 miles you'll pay 1 apple * 1000 miles = 1000 apples as a tax. So no matter if you go once, twice, three times or a hundred times there - you'll be never able to deliver any apple.

Answer: The highest number of apples you can get to Bananaville is 0.
4 0
3 years ago
Does anyone know how to do these maths question???
Dmitry_Shevchenko [17]

Answer:

Part 1) f(g(x))=3(x^2)+2

Part 2) g(f(5))=289

Step-by-step explanation:

we know that

A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function

we have

f(x)=3x+2

g(x)=x^{2}

Part 1) Determine f(g(x))

To find f(g(x)) substitute the function g(x) as the variable in function f(x)

so

f(g(x))=3(x^2)+2

Part 2) Determine g(f(x))

To find g(f(x)) substitute the function f(x) as the variable in function g(x)

so

g(f(x))=(3x+2)^2

For x=5

g(f(5))=(3(5)+2)^2

g(f(5))=289

3 0
2 years ago
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