Question

Sixty flowering plants are planted in a flowerbed. forty of the plants are red-flowering homozygous dominant. twenty of the plants are white-flowering homozygous recessive. the plants naturally pollinate and reseed themselves for several years. in a subsequent year, 178 red-flowered plants, 190 pink-flowered plants, and 52 white-flowered plants are found in the flowerbed. use a chi-square analysis to determine if the population is in hardy-weinberg equilibrium

Answer 1

Answer:

The flowering population is in Hardy Weinberg equilibrium.

Step by Step Explanation:

Total initial population size = 60

As both the populations are homozygous so the frequency of alleles will be,

P = 80/120= 0.66

q = 40/120= 0.33

The predicted frequencies for genotypes once the population has reached Hardy-Weinberg

p2 = 0.4356

2pq= 0.4356

q2 = 0.1089

The number of plants with each type of flower in a papulation of 420 is,

Homozygous dominant= 185

heterozygous= 185

Homozygous recessive= 50

Chi square analysis:

The observed values for red-flowered plants, pink-flowered plants, and white-flowered plants are not significantly different from the expected values predicted by Hardy Weinberg equilibrium.

Phenotype      observed(o)    expected (e)          (o-e)2/e

Red                        178                 185                       0.26

Pink                       190                 185                       0.135

White                     52                   50                     0.08

                                       chi-square = 0.474

With 2 degree of freedom this chi-square gives a p value of 0.7 - 0.8, which is not significant.