The ordered pairs (2, -17) and (5, -35) are solutions to which of the following equations?

Mathematics

1 answer:

ololo11 [35]3 years ago

6 0

Answer:

Step-by-step explanation:the answer to this problem is..

D. y = -6x - 5

Lets check

(2,-17)

Substituting y = -17 and x = 2 , we get,

-17 = -6 (2) -5

-17 = -12 - 5

-17 = -17

(5 , -35)

Substituting y = -35 and x = 5 , we get,

-35 = -6 (5) - 5

-35 = -30 - 5

-35 = -35

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Which equation represents this statement?

Digiron [165]

Answer:

2n - 10 = 12

Step-by-step explanation:

the difference of twice a number and 10 is equal to 12

= twice a number minus 10 equal to 12

=> 2n - 10 = 12

4 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then