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Aliun [14]
4 years ago
8

In a pizza store, there are six possible toppings. On a large pizza, you can have 3 toppings. How many combinations of pizza top

pings are there?
A. 10

B. 15

C. 30

D. 60

These are the only answer choices. I got 120, however. If I am correct, please put that or any other answer instead! Thank you.

:)
Mathematics
1 answer:
valina [46]4 years ago
8 0

Answer:

20

Step-by-step explanation:

The questions asks about Combinations of Pizza toppings, so by employing the Combination Formula:

C(n, k) = \frac{n!}{k!(n-k)!}

C(6, 3) = \frac{6!}{3! \cdot 3!} = \frac{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2}{3 \cdot 2 \cdot 3 \cdot 2} = 20

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makvit [3.9K]

Answer:

777

Step-by-step explanation:

3 0
3 years ago
Need Help Please I'm Out Of Time ;( The point (-2, 7) is graphed on a coordinate plane. The point is located 2 units ______ the
zysi [14]

Answer:

Left, Up

Step-by-step explanation:

Since -2 is to the left of 0 on the x-axis, we are moving left 2 units.

Since 7 is above 0 on the y-axis, we are moving up 7 units.

7 0
3 years ago
Solve each triangle for the missing values shown. Show all work necessary. Use exact values
Gelneren [198K]

3)

Cos 60°= \frac{1}{2} = \frac{Adjacent} {Hypotenuse} = \frac{y} {10} \\\\ 2y=10 \\\\ y=5

Now, use Pythagoras theorem to find x

x^2+y^2=10^2 \\\\ \to x^2+5^2=10^2 \\\\ \to x^2+25=100 \\\\ \to x^2 = 100-25 \\\\ \to x^2= 75 \\\\ \to x= \sqrt{75} \\\\ \bf 5 \sqrt{3}

Similarly,

4)

Sin 45°= \frac{1}{\sqrt{2}} = \frac{Opposite} {Hypotenuse} =\frac{2 \sqrt{2}} {a} \\\\ a= 2 \sqrt{2} \times \sqrt{2} \\\\ a=4

Now, use Pythagoras theorem to find b

b^2+(2 \sqrt{2}) ^2=a^2 \\\\ \to b^2+8=4^2 \\\\ \to b^2=16-8  \\\\ \to b^2 = 8\\\\ \to b= \sqrt{8} \\\\ \bf b=2 \sqrt{2}

You can solve all of them in a similar way.

: )

7 0
3 years ago
jesse bought 2 sheets of stamps. on each sheet there are 5 rows of stamps with 6 stamps in each row. how much did he buy.
lana [24]

Answer:

he bought 60 stamps

Step-by-step explanation:

6*5=30

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5 0
3 years ago
Given:
Fynjy0 [20]

Answer:

Option B is correct.

\triangle RST \cong \triangle TUR  

Step-by-step explanation:

Given: RSTU is a parallelogram.

By definition of parallelogram, two pairs of opposite sides are congruent in length.

⇒TU \cong RS and TS \cong RU

In triangle RST and  triangle TUR

RS \cong TU  [Side]  

TS \cong RU  [Side]

RT \cong RT   [Common side]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of other triangle, then the triangles are congruent.

then, by SSS postulates we have;

\triangle RST \cong \triangle TUR    


5 0
4 years ago
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