Answer:
The molarity of the Pb(NO3)2 solution is 0.24 M
Explanation:
Assuming there was no loss during filtration, we can calculated amount of moles Pb(NO3)2 from the 13.25 g of PbCl2 ussing molar mass of PbCl2
13.25 g / 278.1 g = 0.04 moles of PbCl2
According balanced equation 2NaCl + Pb(NO3)2 = 2NaNO3 + PbCl2, 1 mol of Pb(NO3)2 produces 1 mol of PbCl2. So, 0.04 moles of Pb(NO3)2 produces PbCl2
Molarity is = moles of solute/volumen of solution (L)=0.04/0.2= 0.24
I hope my answer helps you
Answer:
0.4
Explanation:
Given parameters:
Mass of NaCl = 0.564g
Mass of KCl = 1.52g
Mass of LiCl = 0.857g
Unknown:
Mole fraction of KCl = ?
Solution:
First, find the number of moles of the given species;
Number of moles =
Molar mass of KCl = 39 + 35.5 = 74.5g/mol
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Molar mass of LiCl = 7 + 35.5 = 42.5g/mol
Number of moles of KCl = = 0.02mol
Number of moles of NaCl = = 0.0096mol
Number of moles of LiCl = = 0.02mol
Sum of moles = 0.02mol + 0.0096mol + 0.02mol = 0.0496mol
Mole fraction of KCl = = 0.4
Ionic bonds happen when Metals give electron to non-metals and covalent bonds happen when Non-metals give electrons away. Knowing this:
-NaF = ionic (Na is a metal, F is a non-metal)
-NF3 = Covalent (N is a non-metal, F is a non-metal)
-SiF4 = Ionic (Si is a metalloid, F is non-metal)
-CaF2 = ionic (Ca is a metal, F is a non-metal)
-NH4F = covalent (N is a non-metal, H is a non-metal, F is a non-metal)
Hope this helps
Answer:
Deep partial-thickness wounds
Answer:
a) fraction of carbon−14 in a piece of charcoal remains after 14.0 years.
b) fraction of carbon−14 in a piece of charcoal remains after
c) fraction of carbon−14 in a piece of charcoal remains after .
Explanation:
The fraction of a radioactive isotope remaining at time t is given by:
Taking log both sides:
[A] = fraction at given time t
= half life of the carbon−14 =5,730 years
a)When , t = 14 years
b)When , t =
c)When , t =