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Tpy6a [65]
3 years ago
5

 what is 19.8-17.1

Chemistry
2 answers:
Ostrovityanka [42]3 years ago
7 0

Answer: it should be 2.8

Explanation:

irina1246 [14]3 years ago
7 0
It’s 2.7 although isn’t that math, not chemistry
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Https://aoa.sooschools.com/media/a_scigen02_2016/3/s803_31.gif
telo118 [61]

The pH scale was given by Sorensen to quanitatively define strength of an acid and base

the pH scale extends from 0 to 14

For acids

The pH should be less than 7 [always]

For base

The pH should be more than 7 [always]

The pH seven is of neutral solution

pH = -log[H+]

Thus lower the pH higher the concentration of hydronium ion or protons produced by an acid

thus for the given pH scale interval [0-3] it represents strong acid [Which will give high concentration of protons on dissociation]

4 0
3 years ago
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An exergonic reaction __________ free energy, and an endergonic reaction __________ free energy.
Rashid [163]
An exergonic reaction proceeds with net release of free energy.
An endergonic reaction absorbs free energy
8 0
2 years ago
All rocks can form into other types of rocks
natka813 [3]

Answer:false

Explanation:

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2 years ago
The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.
Kitty [74]

Answer:

a) The theoretical yield is 408.45g of BaSO_{4}

b) Percent yield = \frac{realyield}{408.45g}*100

Explanation:

1. First determine the numer of moles of BaCl_{2} and Na_{2}SO_{4}.

Molarity is expressed as:

M=\frac{molessolute}{Lsolution}

- For the BaCl_{2}

M=\frac{1.75molesBaCl_{2}}{1Lsolution}

Therefore there are 1.75 moles of BaCl_{2}

- For the Na_{2}SO_{4}

M=\frac{2.0moles[tex]Na_{2}SO_{4}}{1Lsolution}[/tex]

Therefore there are 2.0 moles of Na_{2}SO_{4}

2. Write the balanced chemical equation for the synthesis of the barium white pigment, BaSO_{4}:

BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the BaCl_{2}:

\frac{1.75}{1}=1.75

- For the Na_{2}SO_{4}:

\frac{2.0}{1}=2.0

As the BaCl_{2} is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = \frac{realyield}{theoreticalyield}*100

Percent yield = \frac{realyield}{408.45g}*100

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0
3 years ago
How many molecules are contained in 125 grams of water, H20?
sergejj [24]
Answer:

18,01528

Explanation:
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2 years ago
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