Solid cesium bromide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell
is 428.7 pm, what is the density of CsBr in g/cm3.
1 answer:
Answer:

Explanation:
Let recall the crystal structure of CsBr obtains a BCC structure. In a BCC structure, there exist only two atom per cell.
The density d of CsBr in g/cm³ can be calculated by using the formula:

where;
z = 1 mole of CsBr
edge length = 428.7 pm = (4.287 × 10⁻⁸)³ cm
molar mass of CsBr = 212.81 g/mol
avogadro's number = 6.023 × 10²³



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