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Yanka [14]
1 year ago
7

Silicon is prepared by the reduction of K₂SiF6 with Al. Write the equation for this reaction. (Hint: Can F⁻ be oxidized in this

reaction? Can K⁺ be reduced?)
Chemistry
1 answer:
BlackZzzverrR [31]1 year ago
3 0

4Al + 3K2SiF6 = 6KF + 3Si + 4AIF3 is the reaction for preparation of silicon by the reduction of K₂SiF6 with Al.

AlF3xH2O-based inorganic compounds are referred to as aluminium fluoride. They are all solids without colour. Aluminium fluoride is a crystalline (sand-like), odourless, white, or colourless powder. In addition to being used to make aluminium, it also functions as a flux in welding processes and in ceramic glazes and enamels.

Silicon (Si) is created by reducing potassium silicofluoride with aluminium as the reducing agent (K2SIF6). While K2SiF6 is reduced to Si in this equation, aluminium is oxidised to aluminium fluoride. As a result, the balanced equation describing aluminum's reduction of K2SiF6 to silicon non-metal is as follows: 4Al + 3K2SiF6 = 6KF + 3Si + 4AIF3

Learn more about aluminium fluoride here:

brainly.com/question/17131529

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Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
3 years ago
The electronegativity is 2.1 for h and 1.9 for pb. based on these electronegativities pbh4 would be expected to
Sedbober [7]
PbH4 will be formed as a result of a polar covalent bond between the H and the Pb.

Since H is more electronegative than the Pb, it is, thus, expected that the H would be able to pull the electron charge towards itself. This will result in the H being negative.

Based on this:
PbH4 would be expected to <span>have polar covalent bonds with a partial negative charges on the H atoms. </span>
8 0
3 years ago
The periodic law states that the physical and chemical properties tend to repeat periodically when elements are arranged accordi
Ivanshal [37]
Atomic number or the number of protons in the element.
6 0
3 years ago
Plant can accomplish something animal cells can’t. They can make their own food during
Kruka [31]

Answer:

Photosynthesis is the answer.

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER QUICKLY !!! FOR MY CHEMISTRY CLASS !!!!!
Sergio039 [100]

The density of the unknown metal, given the data is 1.67 g/mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the above formula, we can determine the density of the unknown metal. Details below:

<h3>How to determine the density </h3>
  • Mass of unknown metal = 20 - 0 = 20 g
  • Volume of unknown metal = 12 - 0 = 12 mL
  • Density of unknown metal =?

Density = mass / volume

Density of unknown metal = 20 / 12

Density of unknown metal = 1.67 g/mL

Thus, the density of unknown metal is 1.67 g/mL

Learn more about density:

brainly.com/question/952755

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4 0
1 year ago
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