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3 years ago

11

Using EEGs, researchers try to identify __________ while subjects are engaged in different tasks. A. brain patterns B. mental ca

pabilities C. electrical activity D. brain waves

1 answer:

GuDViN [60]3 years ago

8 0

Answer:

A. Brain patterns

Explanation:

Got it right on the quiz.

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I NEED THE RIGHT ANSWER ASAP NO LINKS !!!<br> This is a Science question

Tanya [424]

Answer:

The answer is the top choice. (-1)

Explanation:

We are dealing with a negative number here, so we should start at negative five on the number line. From here we see that we are subtracting a negative number from it, which means we are really adding. (Review your rules for negative signs if this doesn't make sense.) So we add 4 to -5, and we get -1. Thus, we get the top choice.

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3 years ago

a ball is launched upward at an angle from the ground. which way does its acceleration point at the top?

yawa3891 [41]

Answer:

it's acceleration points tangentially to its trajectory in the direction of its motion at the top.

cause only it's horizontal velocity acts at the top. and it will be horizontal in the direction of it's motion.

4 0

3 years ago

A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The

mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

$v = v_{o}+a\cdot t$

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t$ - Time, measured in seconds.

Now, we clear acceleration within expression:

$a = \frac{v-v_{o}}{t}$

Initial and final velocities are now converted from kilometers per hour into meters per second:

$v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v_{o} = 30\,\frac{m}{s}$

$v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v = 37.5\,\frac{m}{s}$

If we know that $t = 3.5\,s$ , then, the average acceleration of the car is:

$a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}$

$a = 2.143\,\frac{m}{s^{2}}$

The average acceleration of the car is 2.143 meters per square second.

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3 years ago

In the warm up, you reviewed the equation to calculate kinetic energy. What question could you ask about kinetic energy which wi

shutvik [7]

Explanation:

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3 years ago

Read 2 more answers

Blake has a mass of 72kg and Denise has a mass of 53kg. Blake and Denise are standing 2 meters apart on the dance floor. Denise

ivann1987 [24]

Answer:

6.36*10^-8 N

Explanation:

The magnitude of gravitational force of attraction is usually given by the formula

F = Gm1m2/r², where

F = magnitude of the force required

G = gravitational constant, 6.67*10^-11 m3 kg^-1 s^-2

m1 = mass of the first body, 72 kg

m2 = mass of the second body, 53 kg

r = radius between the bodies themselves, 2 m

Now, when we apply the formula directly, we get

F = (6.67*10^-11 * 72 * 53) / 2²

F = (6.67*10^-11 * 3816) / 4

F = 2.55*10^-7 / 4

F = 6.36*10^-8 N

8 0

3 years ago