Answer:
![D=3.5\ gr/cm^3](https://tex.z-dn.net/?f=D%3D3.5%5C%20gr%2Fcm%5E3)
Step-by-step explanation:
<u>Density</u>
The density of an object of mass m and volume V is given by
![\displaystyle D=\frac{m}{V}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20D%3D%5Cfrac%7Bm%7D%7BV%7D)
It can be expressed in common units like
or any other combination of proper mass [M] by volume [V] units.
The data provided in the question is
![m=200\ mg = 0.2\ gr](https://tex.z-dn.net/?f=m%3D200%5C%20mg%20%3D%200.2%5C%20gr)
![V=0.057\ cm^3](https://tex.z-dn.net/?f=V%3D0.057%5C%20cm%5E3)
Thus, the measured density is
![\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20D%3D%5Cfrac%7B0.2%5C%20gr%7D%7B0.057%20%5C%20cm%5E3%7D)
![\boxed{D=3.5\ gr/cm^3}](https://tex.z-dn.net/?f=%5Cboxed%7BD%3D3.5%5C%20gr%2Fcm%5E3%7D)
We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.
The answer is this: $3.60
4 x 10 = 40 - 0.4 = 3.6
Given:
The scale of a map is
.
The distance between two buildings is 60 miles.
To find:
The distance between the given building on the map.
Solution:
We have,
![\dfrac{3}{4}\ in=80\ miles](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B4%7D%5C%20in%3D80%5C%20miles)
It means, 80 miles in real life =
on the map.
1 mile in real life =
on the map.
60 mile in real life =
on the map.
=
on the map.
=
on the map.
Therefore, the buildings are
apart on the map.
Answer:
-n← 2 2/3
Step-by-step explanation:
first combine like terms, and then simplify
Answer:
Starting from the origin go right 4 units in order to get 4 as your x value and then go down 3 units in order to get -3 as your y value.
Step-by-step explanation:
Do i need to be more specific?