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vlabodo [156]
3 years ago
9

When the energy needed for bond making is _______ the energy needed for bond breaking, the reaction is endothermic.

Chemistry
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

When the energy needed for bond making is <u>higher than</u> the energy needed for bond breaking, the reaction is endothermic.

Explanation:

An endothermic reaction is that in which the energy of the products or bond making is higher than the energy of the reagents or bond breaking, therefore needs energy to take place.

solmaris [256]3 years ago
7 0
The answer is exothermic
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What is the decay mode of radium-226?
inn [45]

Answer:

Radium-226 is a radioactive decay product in the uranium-238 decay series and is the precursor of radon-222. Radium-228 is a radioactive decay product in the thorium-232 decay series. Both isotopes give rise to many additional short-lived radionuclides, resulting in a wide spectrum of alpha, beta and gamma radiations.

6 0
3 years ago
I need help with this question ASAP
sladkih [1.3K]

the answer is thermal.......

4 0
3 years ago
Complete the reaction by writing the formulas of the products. CH 3 COOH + NH 3 − ⇀ ↽ − CH_{3}COONH_{4}^{+} CH 3 COONH + 4 The K
cricket20 [7]

Answer:

Products are favored.

Explanation:

The acid-base reaction of CH₃COOH (acid) with NH₃ (base) produce:

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr = ?

It is possible to know Kr of the reaction by the sum of acidic dissociations of the half-reactions. That is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ Ka = 1.8x10⁻⁵

NH₃ + H⁺ ⇄ NH₄⁺ 1/Ka = 1/ 5.6x10⁻¹⁰ = 1.8x10⁹

___________________________________

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr =  1.8x10⁻⁵×1.8x10⁹ = <em>3.2x10⁴</em>

<em> </em>

As Kr is defined as:

Kr =  [CH₃COO⁻] [NH₄⁺] / [CH₃COOH] [NH₃]

And Kr is > 1  

[CH₃COO⁻] [NH₄⁺] > [CH₃COOH] [NH₃],

showing <em>products are favored</em>.

4 0
3 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
4 years ago
M
vlada-n [284]

Answer:

El cocodrilo se arrastró durante 20.833 segundos.

Explanation:

El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: <em>"Un cocodrilo se arrastró 25 metros hacia la derecha con una  rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"</em>

Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:

t = \frac{x}{v} (1)

Donde:

x - Distancia recorrida, en metros.

v - Rapidez del cocodrilo, en metros por segundo.

t - Tiempo, en segundos.

Si x = 25\,m y v = 1.2\,\frac{m}{s}, entonces el tiempo empleado por el cocodrilo es:

t = \frac{25\,m}{1.2\,\frac{m}{s} }

t = 20.833\,s

El cocodrilo se arrastró durante 20.833 segundos.

<em />

8 0
3 years ago
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