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Rina8888 [55]
3 years ago
10

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
6 0
121 = 112 - k • -3
9 = k • -3
k = -3
Morgarella [4.7K]3 years ago
6 0
K=3 or 3=k how ever you word it
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If anyone can, please help me. I have to determine the value of x.
zzz [600]

Answer:

60 I think

Step-by-step explanation:

draw a straight line to make it a triangle then you know that angles in a triangle add up to 180.

so,

180-140=40

180-100=80

40+80=120

180-120=60

x=60

I think it's 60

6 0
3 years ago
Consider two competing firms in a declining industry that cannot support both firms profitably. Each firm has three possible cho
yaroslaw [1]

Answer:

a) attached below

b)  ( T,T )

c) The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

d) The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 )

Step-by-step explanation:

A) write down the game in matrix form

let: E = exit at the industry immediately

     T = exit at the end of the quarter

     N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

C) Find the pure-strategy Nash equilibria

The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 ) since T is weakly dominated then the mixed strategy will be NE

Assume that P is the probability of firm 1 exiting immediately ( E )

and q is the probability of firm 1 staying till next term ( N ) ∴ q = 1 - P.

hence the expected utility of firm 2 choosing E = 0 while the expected utility of choosing N = 4p - 2q .

The expected utilities of E and N to firm 2 =

0 = 4p - 2q = 4p - 2 ( 1-p) = 6p -2 which means : p = 1/3 , q = 2/3

4 0
3 years ago
A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 15 minutes. Air traffic co
Sladkaya [172]

Answer:

y = (1/2)x + 15

Step-by-step explanation:

First, we need to identify the parts of the problem that we already know:

1) The pilot was originally scheduled to depart at 1600 (4:00 pm).

2) The pilot's departure was delayed by 15 minutes.

3) the traffic control approved a new flight plan that would allow the pilot to travel to her destination two times faster than her original flight plan.

For the problem's sake, let us pretend that the pilot's original flight plan was going to take two hours. Had he/she left at 4:00 pm, the pilot would have landed at 6:00 pm.

With a delay of 15 minutes, the duration of the flight would still remain constant, so the pilot would arrive at their destination two hours later, at 6:15 pm.

With the new flight plan, the pilot's travel time would be cut in half, so it would be 1/2 of x (time, in minutes, of original flight). Thus, her new flight time would only be one hour (60 minutes).

So, now we have to subtract 1/2 from the original flight time, as well as adding the 15 minute delay for departure. Now we can create a formula:

y = (1/2)x + 15

Y equals the total amount of time (in minutes) that it would take for the plane to leave. We divide x (total time of original flight) by 2, because her new flight plan will be twice as fast. Then we have to take into account the extra 15 minute delay!  

8 0
3 years ago
Please help me!!!!!!
Rom4ik [11]

Answer:

105

Step-by-step explanation:

LN = 6x

LN = LM + MN ➡ LN = 4x + 8 + 27 so 6x = 4x + 8 + 27

2x = 35 and x = 17.5

6 × 17.5 = 105

5 0
3 years ago
Read 2 more answers
What’s the distance between (-5 , -3) and (-4 ,-2)
zaharov [31]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
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