1.7x 10 =17
Hope this helps
<span>A. H(w) gets very large. </span>
Answer:
x=-3, y=-6. (-3, -6).
Step-by-step explanation:
-4x+y=6
-5x-y=21
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-9x=27
x=27/-9
x=-3
-5(-3)-y=21
15-y=21
y=15-21
y=-6
Answer:
Hence, Grasshopper will land on the ground after 1.5 sec.
Step-by-step explanation:
It s given that:
The height, in feet, of the grasshopper above the ground after t seconds is modeled by the function:
![h(t)=-t^2+\dfrac{4}{3}t+\dfrac{1}{4}](https://tex.z-dn.net/?f=h%28t%29%3D-t%5E2%2B%5Cdfrac%7B4%7D%7B3%7Dt%2B%5Cdfrac%7B1%7D%7B4%7D)
Now we are asked to find:
In how many seconds will the grasshopper land on the ground?
i.e. we have to find the value of t such that h(t)=0
i.e.
![-t^2+\dfrac{4}{3}t+\dfrac{1}{4}=0](https://tex.z-dn.net/?f=-t%5E2%2B%5Cdfrac%7B4%7D%7B3%7Dt%2B%5Cdfrac%7B1%7D%7B4%7D%3D0)
i.e. we need to find the roots of the given quadratic equation.
On solving the quadratic equation or plotting it's graph we could observe that the point where h(t)=0 are:
![t=-\dfrac{1}{6},t=\dfrac{3}{2}](https://tex.z-dn.net/?f=t%3D-%5Cdfrac%7B1%7D%7B6%7D%2Ct%3D%5Cdfrac%7B3%7D%7B2%7D)
As time can't be negative hence we will consider:
![t=\dfrac{3}{2}=1.5sec](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B3%7D%7B2%7D%3D1.5sec)
Hence, grasshopper will land on the ground after 1.5 sec.
Answer:
-0.8x + 4.8y + 16
Step-by-step explanation:
4(0.5x+2.5y-0.7x-1.3y+4) = 4( 0.5x - 0.7x + 2.5y - 1.3y + 4)
= 4( -0.2x + 1.2y + 4)
= 4*(-0.2x) + 4 *1.2y + 4*4
= -0.8x + 4.8y + 16