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slava [35]
3 years ago
11

Pls help I’m about to cry I cant do this it’s due in ten min

Chemistry
1 answer:
ella [17]3 years ago
7 0

Answer:

C

Explanation:

When a dentist has you do xrays there are waves thats what the vest is for

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How many moles of ammonium sulfate can be from the reaction of 30.0 mol of NH3 with H2SO4 according to the following equation: 2
marysya [2.9K]

Answer:

15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

Explanation:

Given data:

Number of moles of ammonium sulfate formed = ?

Number of moles of ammonia = 30.0 mol

Solution:

Chemical equation:

2NH₃  +   H₂SO₄  →  (NH₄)₂SO₄

Now we will compare the moles of ammonium sulfate with ammonia.

                           NH₃           :           (NH₄)₂SO₄

                             2              :               1

                            30.0          :              1/2×30.0 = 15.0 mol

So 15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

7 0
3 years ago
Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.
Hatshy [7]
Following reaction occurs in the given electrochemical system:
Fe^{2+} + Zn → Fe + Zn^{2+}
Thus, under standard conditions
E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
where, E^{0}Fe2+/Fe = standard reduction potential of Fe2+/Fe = -0.44 v
E^{0}Zn2+/Zn = standard reduction potential of Zn2+/Zn = -0.763 v

E(0) = 0.323 v
now, we know that, ΔG(0) =-nFE(0) ............... (1)
Also, ΔG^{0} = -RTln(K) ............ (2)

On equating and rearranging equation 1 and 2, we get
K = exp( \frac{nFE(0)}{RT} )= exp (\frac{2X96500X0.323}{8.314X298}) = 8.46 x 10^{10}

7 0
3 years ago
Calculate e°cell for a silver-aluminum cell in which the cell reaction is al(s) + 3ag+(aq) → al3+(aq) + 3ag(s) –2.46 v 0.86 v –0
tekilochka [14]
When E° cell is an electrochemical cell which comprises of two half cells.
 
So,

when we have the balanced equation of this half cell :

Al3+(aq) + 3e- → Al(s)   and E°1 = -1.66 V 

and we have  also this balanced equation of this half cell :

Ag+(aq)  + e- → Ag(s)  and E°2 = 0.8 V 

so, we can get E° in Al(s) + 3Ag (aq) → Al3+(aq) + 3Ag(s)

when E° = E°2 - E°1

∴E° =0.8 - (-1.66)

      = 2.46 V

∴ the correct answer is 2.46 V




6 0
3 years ago
NEED ASAP WILL MARK BRAINLIEST ON TIMER
vladimir1956 [14]

Answer:

The answer is 2.660 mol/l

Explanation:

Given: n= 0.0665, v= 25.00ml

Required: C

C (molarity)= n (of solute)/ v (of solvent) [ standard unit: mol/l]

First convert volume of solvent in its standard unit, i.e. litres(L)

v= 25.00ml/1000= 0.02500L

C = 0.0665 mol / 0.02500 L= 2.660 mL (In proper significant digits i.e. 4 sigdigs)

Therefore, The molarity of the sulfuric acid is 2.660 mol/L :)

3 0
3 years ago
As electricity flows through a copper wire, the temperature of the wire increases. Some parts of the wire get warmer than others
mezya [45]

Answer:

Conduction

Explanation:

The heat can be transferred in the substances in three ways: conduction, convection, and radiation.

The conduction happens inside the material, usually a solid, and the heat flows as the molecules of the substance are agitated. The convection happens when there are different substances in touch, so it is the heat passage from a solid to a liquid or gas, from a gas to a liquid or vice versa. The radiation occurs between substances that are far away and the heat flows by electromagnetic waves.

Thus, in the wire, the heat flows by conduction.

3 0
3 years ago
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