Answer:
The answer to your question is 280 g of Mg(NO₃)₂
Explanation:
Data
Efficiency = 30.80 %
Mg(NO₃)₂ = ?
Magnesium = 147.4 g
Copper (II) nitrate = excess
Balanced Reaction
Mg + Cu(NO₃)₂ ⇒ Mg(NO₃)₂ + Cu
Reactants Elements Products
1 Mg 1
1 Cu 1
2 N 2
6 O 6
Process
1.- Calculate the theoretical yield
Molecular weight Mg = 24
Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)
= 24 + 28 + 96
= 148 g
24 g of Mg -------------------- 148 g of Mg(NO₃)₂
147.4 g of Mg ------------------- x
x = (147.4 x 148) / 24
x = 908.96 g of Mg(NO₃)₂
2.- Calculate the Actual yield
yield percent = 
Solve for actual yield
Actual yield = Yield percent x Theoretical yield
Substitution
Actual yield = 
x 908.96
Actual yield = 279.95 ≈ 280g
Answer:
An equal force acts in the opposite direction.
Explanation:
Answer:
Ksp FeS = 5.2441 E-18
Explanation:
S S S
∴ Ksp = [Fe2+]*[S2-].....solubility product constant
∴ [S2-] = 2.29 E-9 M = S
⇒ Ksp = (S)(S) = S²
⇒ Ksp = (2.29 E-9)²
⇒ Ksp = 5.2441 E-18
Answer:
It would be 3 times as much gravity or 7 times
Explanation:
Answer : The number of moles of water will be, 1.235 moles
Solution : Given,
Mass of 
= 42 grams
Molar mass of = 34 g/mole
First we have to calculate the moles of
Now we have to calculate the moles of water.
The balanced chemical reaction will be,
From the balanced reaction, we conclude that
As, 2 moles of decomposes to give 2 moles of water
So, 1.235 moles of decomposes to give 1.235 moles of water
Therefore, the number of moles of water will be, 1.235 moles
