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Umnica [9.8K]
3 years ago
5

`which of the following is true ?

Chemistry
2 answers:
Sidana [21]3 years ago
8 0
C. I took this test!!
wlad13 [49]3 years ago
3 0
Answer:

C) since electrons have mass, we must always consider them to have particle properties and never wavelike properties.
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What is the difference between corrosive and flammable
castortr0y [4]
- Corrosive<span> chemicals eat away and destroy things. </span>Flammable<span> things can be burned with fire. </span>
3 0
3 years ago
How many moles of h20 are produced from 3 moles of oxygen?
Ierofanga [76]

Answer:

Stoichiometric Values in a Chemical Reaction

Explanation:

The coefficients next to the reactants and products are the stoichiometric values. They represent the number of moles of each compound that needs to react so that the reaction can go to completion.

6 0
3 years ago
The combustion of Ibuprofen C13H18O2 produces water and carbon
prohojiy [21]

Answer:

277.7 g of CO2

Explanation:

Equation of reaction

C13H18O2 + 11O2 ---> 13CO2 + 9H2O

From the equation of reaction

1 mole of ibuprofen produces 13 moles of CO2

Molar mass of ibuprofen is 206g

Molar mass of CO2 is 44g

13 moles of CO2 weighs 572g

Therefore, 100g of ibuprofen will produce (100×572)/206 of CO2

= 277.7g

6 0
3 years ago
If I pour Sodium Hydroxide to Copper Sulfate, would this be a physical or chemical change?
gizmo_the_mogwai [7]
It would be a chemical change.
Hope this helps!
5 0
3 years ago
Read 2 more answers
An aqueous solution contains 3.7 % NaCl by mass.
Tanya [424]

Answer:

- Molality:

m=0.65m

- Mole fraction:

x_{NaCl}=0.0116\\x_{H_2O}=0.9884

Explanation:

Hello,

- Molality: in this case, the solution is formed by 3.7% by mass of sodium chloride and water, thereby, we assume we have 100 g of solution in order to find the mass of sodium chloride as shown below:

m_{NaCl}=\frac{100g*3.7\%}{100\%} =3.7g

Hence, the moles of sodium chloride and kilograms of water are:

n_{NaCl}=\frac{3.7g}{58.45g/mol} =0.063molNaCl\\m_{H_2O}=100g-3.7g=96.3g*\frac{1kg}{1000g}=0.0963kgH_2O

With which the molality results:

m=\frac{n_{NaCl}}{m_{H_2O}}=\frac{0.063molNaCl}{0.0963kg}=0.65m

- Mole fraction: in this case, since we have previously computed the moles of sodium chloride, we now compute the moles of water as:

n_{H_2O}=\frac{96.3g}{18g/mol} =5.35molH_2O

Thus, the mole fraction of sodium chloride is:

x_{NaCl}=\frac{0.063}{5.35+0.063} =0.0116\\x_{H_2O}=\frac{5.35}{5.35+0.063} =0.9884

Best regards.

3 0
3 years ago
Read 2 more answers
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